Math Problem Statement

  1. State and prove Cauchy's mean value theorem 8mar

Solution

Cauchy's Mean Value Theorem

Statement: Let ff and gg be two functions that are continuous on the closed interval [a,b][a, b] and differentiable on the open interval (a,b)(a, b), where a<ba < b. Additionally, suppose that g(x)0g'(x) \neq 0 for all x(a,b)x \in (a, b). Then, there exists a point c(a,b)c \in (a, b) such that:

f(b)f(a)g(b)g(a)=f(c)g(c)\frac{f(b) - f(a)}{g(b) - g(a)} = \frac{f'(c)}{g'(c)}

Proof:

  1. Assumptions:

    • ff and gg are continuous on [a,b][a, b].
    • ff and gg are differentiable on (a,b)(a, b).
    • g(x)0g'(x) \neq 0 for all x(a,b)x \in (a, b).
  2. Define a new function: We define a function h(x)h(x) to apply Rolle's Theorem, which is a key part of the proof. Let:

    h(x)=f(x)λg(x)h(x) = f(x) - \lambda g(x)

    where λ\lambda is a constant to be determined.

  3. Determine λ\lambda: We want to choose λ\lambda so that h(a)=h(b)h(a) = h(b). This condition will allow us to apply Rolle's Theorem.

    h(a)=f(a)λg(a),h(b)=f(b)λg(b)h(a) = f(a) - \lambda g(a), \quad h(b) = f(b) - \lambda g(b)

    Setting h(a)=h(b)h(a) = h(b), we get:

    f(a)λg(a)=f(b)λg(b)f(a) - \lambda g(a) = f(b) - \lambda g(b)

    Solving for λ\lambda, we find:

    λ=f(b)f(a)g(b)g(a)\lambda = \frac{f(b) - f(a)}{g(b) - g(a)}

  4. Apply Rolle's Theorem: Since h(a)=h(b)h(a) = h(b), by Rolle's Theorem, there exists a point c(a,b)c \in (a, b) such that h(c)=0h'(c) = 0. Now, we compute h(x)h'(x):

    h(x)=f(x)λg(x)h'(x) = f'(x) - \lambda g'(x)

    Setting h(c)=0h'(c) = 0, we get:

    f(c)λg(c)=0f'(c) - \lambda g'(c) = 0

    Substituting the value of λ\lambda, we obtain:

    f(c)=λg(c)=f(b)f(a)g(b)g(a)g(c)f'(c) = \lambda g'(c) = \frac{f(b) - f(a)}{g(b) - g(a)} \cdot g'(c)

  5. Conclusion: Therefore, there exists c(a,b)c \in (a, b) such that:

    f(c)g(c)=f(b)f(a)g(b)g(a)\frac{f'(c)}{g'(c)} = \frac{f(b) - f(a)}{g(b) - g(a)}

This completes the proof of Cauchy's Mean Value Theorem.


Would you like more details or have any questions about this theorem?

Related Questions:

  1. How does Cauchy's Mean Value Theorem differ from the standard Mean Value Theorem?
  2. Can you provide an example where Cauchy's Mean Value Theorem is applied?
  3. What are the geometric interpretations of Cauchy's Mean Value Theorem?
  4. How can we generalize Cauchy's Mean Value Theorem to higher dimensions?
  5. How does Rolle's Theorem serve as a foundation for Cauchy's Mean Value Theorem?

Tip:

Always ensure the continuity and differentiability conditions are satisfied before applying the Mean Value Theorems.

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Math Problem Analysis

Mathematical Concepts

Calculus
Mean Value Theorem
Differentiation

Formulas

\frac{f(b) - f(a)}{g(b) - g(a)} = \frac{f'(c)}{g'(c)}
h(x) = f(x) - \lambda g(x)
\lambda = \frac{f(b) - f(a)}{g(b) - g(a)}

Theorems

Cauchy's Mean Value Theorem
Rolle's Theorem

Suitable Grade Level

Undergraduate Calculus