Let's break down the given problem, step by step.

Part A: Determine truth values for the logical expressions

We are given the following truth assignments:

• $A = \text{False}$
• $B = \text{True}$
• $C = \text{False}$
• $D = \text{True}$

We will evaluate each expression based on these truth values.

a. $\left( (C \to B) \to \neg C \right) \leftrightarrow \left( B \to (C \land A) \right)$

• $C \to B$ means "if $C$, then $B$". Since $C = \text{False}$, $C \to B$ is True (implication is true when the premise is false).
• $\neg C$ is the negation of $C$, so $\neg C = \text{True}$.
• $(C \to B) \to \neg C$: $\text{True} \to \text{True} = \text{True}$.
• $C \land A$ is the conjunction of $C$ and $A$. Since both $C = \text{False}$ and $A = \text{False}$, $C \land A = \text{False}$.
• $B \to (C \land A)$: Since $B = \text{True}$ and $C \land A = \text{False}$, $B \to \text{False} = \text{False}$.

So, the expression becomes:
$\text{True} \leftrightarrow \text{False} = \text{False}$.

b. $\left( D \land B \right) \lor \left( A \land C \right) \land B$

• $D \land B$: Since $D = \text{True}$ and $B = \text{True}$, $D \land B = \text{True}$.
• $A \land C$: Since both $A = \text{False}$ and $C = \text{False}$, $A \land C = \text{False}$.
• $\left( A \land C \right) \land B$: $\text{False} \land B = \text{False}$.
• So, $\left( D \land B \right) \lor \left( A \land C \right) \land B = \text{True} \lor \text{False} = \text{True}$.

c. $\left( A \lor B \right) \to C \to \left( B \to (A \lor B) \right)$

• $A \lor B$: Since $A = \text{False}$ and $B = \text{True}$, $A \lor B = \text{True}$.
• $(A \lor B) \to C$: $\text{True} \to \text{False} = \text{False}$.
• $A \lor B = \text{True}$, and $B = \text{True}$, so $B \to (A \lor B)$ is $\text{True} \to \text{True} = \text{True}$.

So, the expression becomes:
$\text{False} \to \text{True} = \text{True}$.

Part B: Constructing truth tables

For Part B, we need to construct truth tables for the given expressions. Let's first write them out clearly.

a. $\left( p \lor q \right) \to r \land \left( \left( r \land p \right) \to r \right)$

This involves 3 variables $p$, $q$, and $r$, so the truth table will have 8 rows (since $2^3 = 8$).

b. $\left( r \land p \right) \to \left[ \left( p \lor q \right) \to \neg p \land \left( p \lor q \right) \right]$

This also involves 3 variables $p$, $q$, and $r$, so it will have 8 rows as well.

Would you like to see the truth table calculations for Part B? Let me know! Also, if you have any questions about the explanation for Part A, feel free to ask.

Here are 5 related questions you might consider:

1. How does the truth table change if one of