A has 4 1st choice, B has 5 1st choice, C has 7 first choice, and D has 12

Thank you for the clarification. Let's reevaluate the results using the correct first-choice vote counts:

### First Round
The first-choice votes are:

- **A**: 4 votes
- **B**: 5 votes
- **C**: 7 votes
- **D**: 12 votes

Since no candidate has a majority (more than 14 out of 28 votes), we will eliminate the candidate with the fewest votes and redistribute those votes.

### Step 1: Eliminate A
- **Candidate A** has the fewest votes (4 votes). We eliminate A.
- The 4 votes for A will be transferred to the second choice on those ballots:
  - All 4 votes go to **D** (since D is the second choice for voters who ranked A first).

Updated vote counts after eliminating A:
- **B**: 5 votes
- **C**: 7 votes
- **D**: 12 + 4 = 16 votes

### Step 2: Majority Check
- **D** now has 16 votes out of 28 total votes, which is a majority.

### Conclusion:
**D** wins with a majority of the votes.

**Winner = D**

Would you like more details or have any questions? Here are some related questions:

1. How does this voting method ensure that the winner has broad support?
2. What might happen in a scenario where multiple candidates are tied for the lowest votes?
3. Can a candidate with fewer first-choice votes still win under Instant Runoff Voting?
4. How does the distribution of second-choice votes impact the final outcome?
5. How could the elimination order affect the winner in different scenarios?

**Tip:** Always double-check the initial vote counts before proceeding with eliminations in Instant Runoff Voting, as each elimination step depends on the accurate redistribution of votes.

Explore the mechanics of Instant Runoff Voting (IRV) through a detailed analysis of a voting scenario involving candidates A, B, C, and D. Learn how votes are redistributed and how the winner is determined based on first-choice votes. Suitable for advanced students and anyone interested in voting theory.

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