Math Problem Statement

Solve the following: 1) 4^2, 2) 2^3, 3) (-4)^3, 4) (-5)^3, 5) -2^3

Solution

Let's solve the problems from the image:

  1. 424^2: 42=4×4=164^2 = 4 \times 4 = 16 Answer: 1616

  2. 232^3: 23=2×2×2=82^3 = 2 \times 2 \times 2 = 8 Answer: 88

  3. (4)3(-4)^3: (4)3=(4)×(4)×(4)=64(-4)^3 = (-4) \times (-4) \times (-4) = -64 Answer: 64-64

  4. (5)3(-5)^3: (5)3=(5)×(5)×(5)=125(-5)^3 = (-5) \times (-5) \times (-5) = -125 Answer: 125-125

  5. 23-2^3: 23=(2×2×2)=8-2^3 = -(2 \times 2 \times 2) = -8 Answer: 8-8

Would you like any additional details or have any questions? Here are some related questions:

  1. What is the difference between (4)3(-4)^3 and 43-4^3?
  2. How do you calculate (3)2(-3)^2 and 32-3^2?
  3. What is the result of 343^4?
  4. How do negative bases affect exponents?
  5. What is the value of (2)4(-2)^4?

Tip: When calculating powers with negative bases, be careful with parentheses. For example, (4)3(-4)^3 is different from 43-4^3.

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Math Problem Analysis

Mathematical Concepts

Exponentiation
Negative Numbers

Formulas

a^n = a × a × ... (n times)

Theorems

Exponentiation with negative bases

Suitable Grade Level

Grades 6-8