Math Problem Statement

Kindly give me the solution on how u get the domain and range and show me the graph F(x)=2x²

Solution

Here's the graph of the function F(x)=2x2F(x) = 2x^2.

Summary:

  • Domain: (,)(-\infty, \infty)
  • Range: [0,)[0, \infty)
  • Vertex: The parabola has a vertex at (0,0)(0, 0) and opens upwards.

Would you like further details or have any questions?

Related Questions:

  1. How do you determine the axis of symmetry for a quadratic function?
  2. What effect does changing the coefficient of x2x^2 have on the shape of the parabola?
  3. How do you find the vertex of a general quadratic function ax2+bx+cax^2 + bx + c?
  4. Can you explain how to find the roots of F(x)=2x2F(x) = 2x^2 using the quadratic formula?
  5. How do you graph a quadratic function that has a linear term (e.g., F(x)=2x2+3xF(x) = 2x^2 + 3x)?

Tip:

Remember, the coefficient of x2x^2 in a quadratic function affects how "wide" or "narrow" the parabola is. The larger the coefficient, the narrower the parabola.

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Domain and Range
Graphing

Formulas

Quadratic function formula F(x) = ax^2 + bx + c

Theorems

Properties of quadratic functions
Vertex form of a parabola

Suitable Grade Level

Grades 10-12