Kindly give me the solution on how u get the domain and range and show me the graph F(x)=2x²

Here's the graph of the function \( F(x) = 2x^2 \). 

### Summary:
- **Domain:** \( (-\infty, \infty) \)
- **Range:** \( [0, \infty) \)
- **Vertex:** The parabola has a vertex at \( (0, 0) \) and opens upwards.

Would you like further details or have any questions?

### Related Questions:
1. How do you determine the axis of symmetry for a quadratic function?
2. What effect does changing the coefficient of \(x^2\) have on the shape of the parabola?
3. How do you find the vertex of a general quadratic function \( ax^2 + bx + c \)?
4. Can you explain how to find the roots of \( F(x) = 2x^2 \) using the quadratic formula?
5. How do you graph a quadratic function that has a linear term (e.g., \( F(x) = 2x^2 + 3x \))?

### Tip:
Remember, the coefficient of \(x^2\) in a quadratic function affects how "wide" or "narrow" the parabola is. The larger the coefficient, the narrower the parabola.

Explore the domain and range of the quadratic function F(x) = 2x² with a detailed graph analysis. Learn how to determine the domain as (-∞, ∞) and the range as [0, ∞), along with the properties of its vertex at (0, 0). Suitable for high school students studying quadratic functions.

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