Math Problem Statement

f(x) = ln 1 + sen x ÷1 − sen

Solution

The function you've written appears to be:

f(x)=ln(1+sin(x)1sin(x))f(x) = \ln\left(\frac{1 + \sin(x)}{1 - \sin(x)}\right)

This expression involves a logarithmic function where the argument is a fraction. Let's break it down:

Simplifying and Understanding the Function

The function is:

f(x)=ln(1+sin(x)1sin(x))f(x) = \ln\left(\frac{1 + \sin(x)}{1 - \sin(x)}\right)

This is a logarithm with a ratio of two terms, 1+sin(x)1 + \sin(x) and 1sin(x)1 - \sin(x). This function may have certain properties such as domain restrictions due to the presence of the sine function and the logarithm.

Domain of f(x)f(x):

For the logarithm function to be defined, the argument must be strictly positive:

1+sin(x)1sin(x)>0\frac{1 + \sin(x)}{1 - \sin(x)} > 0

This means that 1+sin(x)1 + \sin(x) and 1sin(x)1 - \sin(x) must have the same sign (both positive or both negative).

  • 1+sin(x)01 + \sin(x) \geq 0 for all xx, because the sine function oscillates between -1 and 1, so 1+sin(x)1 + \sin(x) is always non-negative.
  • However, 1sin(x)1 - \sin(x) will be positive when sin(x)<1\sin(x) < 1 and will approach zero as sin(x)\sin(x) approaches 1.

Thus, there will be specific intervals where the logarithmic function is valid, depending on the sine value.

Properties of f(x)f(x):

To understand its behavior better, let's try some specific values of xx:

  1. When x=0x = 0, sin(0)=0\sin(0) = 0: f(0)=ln(1+010)=ln(1)=0f(0) = \ln\left(\frac{1 + 0}{1 - 0}\right) = \ln(1) = 0

  2. When x=π2x = \frac{\pi}{2}, sin(π2)=1\sin\left(\frac{\pi}{2}\right) = 1: f(π2)=ln(1+111)f\left(\frac{\pi}{2}\right) = \ln\left(\frac{1 + 1}{1 - 1}\right) This expression is undefined because the denominator becomes zero.

The function is undefined where 1sin(x)=01 - \sin(x) = 0, which occurs when sin(x)=1\sin(x) = 1, i.e., at x=π2+2kπx = \frac{\pi}{2} + 2k\pi, where kk is an integer.

Summary:

The function f(x)=ln(1+sin(x)1sin(x))f(x) = \ln\left(\frac{1 + \sin(x)}{1 - \sin(x)}\right) is well-defined for values of xx where sin(x)1\sin(x) \neq 1, i.e., excluding the points where x=π2+2kπx = \frac{\pi}{2} + 2k\pi, for any integer kk.

Would you like to explore the function further, such as its derivative, integral, or graph? Feel free to ask for more details! Here are some related questions:

  1. How do we find the derivative of f(x)f(x)?
  2. How can we analyze the behavior of this function near the points where it is undefined?
  3. How can we compute the integral of f(x)f(x)?
  4. What are the asymptotic behaviors of the function near the undefined points?
  5. How can we graph f(x)f(x) to visualize its properties?

Tip: When dealing with logarithmic functions that involve trigonometric terms, it’s important to check the domain carefully to avoid undefined expressions.

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Math Problem Analysis

Mathematical Concepts

Logarithmic Functions
Trigonometric Functions
Domain of Functions

Formulas

f(x) = ln((1 + sin(x)) / (1 - sin(x)))

Theorems

Domain of a Logarithmic Function
Trigonometric Function Properties

Suitable Grade Level

Grades 11-12