It seems like there might be a slight formatting issue with the equation you provided. I believe you're trying to express a function that involves a logarithm with the sine function. The formula might be:

$f(x) = \ln \left( \frac{1 + \sin x}{1 - \sin x} \right)$

Is this the correct expression you're asking about?

Let me know if this is the case, and I can help you analyze and simplify the function. If not, feel free to clarify or correct the formula!

Would you like further details or have any questions on this? Here are some follow-up questions to explore this topic:

1. How do you differentiate this function $f(x)$?
2. Can this function be simplified further using trigonometric identities?
3. How do we find the domain of the function $f(x)$?
4. How does this function behave as $x \to \infty$?
5. What are the limits of the function $f(x)$ as $x$ approaches values where $\sin(x) = 1$?

Tip: Remember that the sine function is bounded between -1 and 1, which can help you determine the domain of the logarithmic function.