Math Problem Statement

Given a 3×3 matrix A and a vector b∈R3 . If the equation AX=b has no solution, then det(A)=? Question 7Answer

a. 0

b. 1

c. 2

d. 3

Solution

If the equation AX=bAX = b has no solution, it implies that the matrix AA is singular. A matrix is singular if it does not have an inverse, which occurs if and only if its determinant is zero.

Reasoning:

  • For the equation AX=bAX = b to have a solution, the matrix AA must be invertible, meaning there exists a unique solution X=A1bX = A^{-1}b when the determinant det(A)0\text{det}(A) \neq 0.
  • If det(A)=0\text{det}(A) = 0, the matrix AA is singular, meaning it has no inverse. In this case, AX=bAX = b might have either no solution or infinitely many solutions depending on bb.

Given that the problem specifies that AX=bAX = b has no solution, this is a clear indication that the matrix AA is singular, and therefore:

det(A)=0\text{det}(A) = 0

Conclusion:

The correct answer is:

a. 0

Would you like more details, or do you have any questions?

Here are some related questions:

  1. What does it mean for a matrix to be singular?
  2. How can you determine if a matrix has no inverse?
  3. What is the relationship between the determinant and the invertibility of a matrix?
  4. How does the determinant relate to the solution of a system of linear equations?
  5. What are the implications of det(A)=0\text{det}(A) = 0 for the solutions of AX=bAX = b?

Tip: A determinant of zero indicates that the matrix is singular, meaning the rows or columns are linearly dependent.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Matrix Theory
Determinants

Formulas

Determinant formula for a 3x3 matrix

Theorems

Theorem on invertibility of matrices

Suitable Grade Level

College Level