The image shows a parallelogram with two diagonals drawn, forming triangles within the shape. To determine the congruence statement for the triangles formed by the diagonals, let's analyze the figure.

Congruence Statement:

The triangles formed by the diagonals of a parallelogram are congruent to each other.

If the parallelogram is labeled as $ABCD$ with diagonals $AC$ and $BD$, the triangles $\triangle ABC$ and $\triangle CDA$ are congruent. This is due to the fact that:

1. $AB$ is congruent to $CD$ (opposite sides of a parallelogram are congruent).
2. $BC$ is congruent to $DA$ (opposite sides of a parallelogram are congruent).
3. $AC$ is the same in both triangles (common side).

Therefore, the congruence statement is: $\triangle ABC \cong \triangle CDA$

Would you like more details or have any other questions?

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Here are 5 related questions you might explore:

1. How does the congruence of triangles within a parallelogram help in proving its properties?
2. What are the other properties of parallelograms related to diagonals?
3. How can you use congruent triangles to calculate angles within a parallelogram?
4. What are the conditions under which the diagonals of a parallelogram bisect each other?
5. How can you prove that the diagonals of a parallelogram bisect each other?

Tip: When working with quadrilaterals like parallelograms, always consider the properties of opposite sides and angles to establish relationships between different parts of the figure.