Let's analyze the sequence of operations you've described and apply it to the four given numbers: 2, 6, 8, and 11.

Step-by-Step Calculation

1. Add 7 to the number.
2. Double the result.
3. Subtract 10.
4. Divide by 2.
5. Subtract the original selected number.

Let's apply these operations to each of the four numbers one by one:

1. For the number 2:

   • Add 7: $2 + 7 = 9$
   • Double the result: $9 \times 2 = 18$
   • Subtract 10: $18 - 10 = 8$
   • Divide by 2: $8 \div 2 = 4$
   • Subtract the original number: $4 - 2 = 2$

2. For the number 6:

   • Add 7: $6 + 7 = 13$
   • Double the result: $13 \times 2 = 26$
   • Subtract 10: $26 - 10 = 16$
   • Divide by 2: $16 \div 2 = 8$
   • Subtract the original number: $8 - 6 = 2$

3. For the number 8:

   • Add 7: $8 + 7 = 15$
   • Double the result: $15 \times 2 = 30$
   • Subtract 10: $30 - 10 = 20$
   • Divide by 2: $20 \div 2 = 10$
   • Subtract the original number: $10 - 8 = 2$

4. For the number 11:

   • Add 7: $11 + 7 = 18$
   • Double the result: $18 \times 2 = 36$
   • Subtract 10: $36 - 10 = 26$
   • Divide by 2: $26 \div 2 = 13$
   • Subtract the original number: $13 - 11 = 2$

Conclusion

No matter which number you start with (2, 6, 8, or 11), the final result is always 2.

This happens because the sequence of operations is designed to always yield a fixed number, regardless of the initial input.

Would you like more details or have any questions?

Related Questions

1. What is the algebraic formula that represents these operations?
2. How