Math Problem Statement

Add 7. Double the result. Subtract 10. Divide by 2. Subtract the original selected number. The first number is 1. The 2nd is 6. The 3rd is 9 and the 4th is 11.

Solution

Let's analyze the sequence of operations described:

  1. Add 7 to the original number.
  2. Double the result from step 1.
  3. Subtract 10 from the result of step 2.
  4. Divide by 2 the result of step 3.
  5. Subtract the original number from the result of step 4.

Let's use this process on each number and see if it holds true.

For 1:

  1. 1+7=81 + 7 = 8
  2. 8×2=168 \times 2 = 16
  3. 1610=616 - 10 = 6
  4. 62=3\frac{6}{2} = 3
  5. 31=23 - 1 = 2

For 6:

  1. 6+7=136 + 7 = 13
  2. 13×2=2613 \times 2 = 26
  3. 2610=1626 - 10 = 16
  4. 162=8\frac{16}{2} = 8
  5. 86=28 - 6 = 2

For 9:

  1. 9+7=169 + 7 = 16
  2. 16×2=3216 \times 2 = 32
  3. 3210=2232 - 10 = 22
  4. 222=11\frac{22}{2} = 11
  5. 119=211 - 9 = 2

For 11:

  1. 11+7=1811 + 7 = 18
  2. 18×2=3618 \times 2 = 36
  3. 3610=2636 - 10 = 26
  4. 262=13\frac{26}{2} = 13
  5. 1311=213 - 11 = 2

Summary

In each case, the final result after performing the operations is always 2.

Would you like further details or have any questions?

Here are 5 related questions to expand on this:

  1. How would the result change if the original number was negative?
  2. What happens if you change the operations, such as adding or subtracting different values?
  3. Can you develop a general formula for this sequence of operations?
  4. How would the result differ if you changed the order of operations?
  5. What if you replaced the multiplication by 2 with multiplication by 3?

Tip: When working with sequences of operations, it's often helpful to write down each step to see patterns more easily.