Math Problem Statement

(2+3)(2^2-6+9^2) sum of two cubes

Solution

Let's break down the given expression step by step to understand it.

Step 1: Simplify the expression (2+3)(226+92)(2+3)(2^2-6+9^2)

  1. First, simplify each component:

    • 2+3=52 + 3 = 5
    • 22=42^2 = 4
    • 92=819^2 = 81
    • So, 226+92=46+81=2+81=792^2 - 6 + 9^2 = 4 - 6 + 81 = -2 + 81 = 79
  2. Now, multiply the simplified parts: (2+3)(226+92)=5×79=395(2+3)(2^2-6+9^2) = 5 \times 79 = 395

Step 2: Sum of Two Cubes

The sum of two cubes is expressed as:

a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a + b)(a^2 - ab + b^2)

However, in the expression you provided, there isn't an apparent "sum of two cubes" situation. If you intended to find a sum of cubes or factor an expression like a3+b3a^3 + b^3, please clarify the specific expression you'd like to factor or analyze.

Would you like more details or have any questions?

Here are 5 related questions you might consider:

  1. What is the difference between the sum of cubes and the difference of cubes?
  2. How do you factor 8x3+278x^3 + 27 as a sum of cubes?
  3. Can you apply the sum of cubes to negative numbers?
  4. What are the real-life applications of factoring the sum of cubes?
  5. How would you solve an equation involving the sum of cubes, such as x3+27=0x^3 + 27 = 0?

Tip: When dealing with algebraic expressions, carefully simplify each part before combining them to avoid mistakes in calculations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Polynomials

Formulas

Sum of cubes formula a^3 + b^3 = (a + b)(a^2 - ab + b^2)

Theorems

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Suitable Grade Level

Grades 9-12