The ratio of ages of Meena&Veena is 4:3. The sum of their ages is 28 yrs. The ratio of their ages after 8 years will be in the ratio ?

7:56:7

6:5

6:11

9:5

Given the ratio of ages of Meena and Veena is 4:3, and their sum is 28 years. We need to determine the ratio of their ages after 8 years.

Let's define their ages as follows:
- Meena's age = \(4x\)
- Veena's age = \(3x\)

Given the sum of their ages:
\[
4x + 3x = 28
\]
\[
7x = 28
\]
\[
x = 4
\]

So, Meena's age is:
\[
4x = 4 \times 4 = 16 \text{ years}
\]

Veena's age is:
\[
3x = 3 \times 4 = 12 \text{ years}
\]

After 8 years, their ages will be:
- Meena's age = \(16 + 8 = 24\)
- Veena's age = \(12 + 8 = 20\)

The new ratio of their ages will be:
\[
\frac{24}{20} = \frac{6}{5}
\]

So, the ratio of their ages after 8 years will be \(6:5\).

The correct answer is: **6:5**.

Would you like more details or have any questions?

Here are some related questions you might be interested in:

1. What would be their ages 5 years ago?
2. How do you solve for their ages if the ratio was 5:3 and the sum was 32 years?
3. If Veena was 2 years older than Meena, what would be their current ages?
4. How would the ratio change if their current ages were doubled?
5. What would be the product of their current ages?
6. How do we solve for the ages if the ratio was reversed to 3:4?
7. If the sum of their ages were different, how would that affect the solution?
8. How can we verify the solution using a different method?

**Tip:** When dealing with ratios, always ensure to clearly define variables and set up equations that reflect the given conditions accurately.

Explore how to solve the age ratio problem involving Meena and Veena. Given their initial ages and the ratio, learn step-by-step how their ages will change after 8 years and what the new ratio will be. Suitable for Grades 6-8 students.

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