Math Problem Statement

Using the method of u-substitution, evaluate the integral ∫ from 1 to 4 of (5x - 3)^5 dx.

Solution

Let's break down the given integral using u-substitution. The integral is:

14(5x3)5dx\int_1^4 (5x - 3)^5 \, dx

We are asked to apply the method of u-substitution where the general form is:

abf(g(x))g(x)dx=g(a)g(b)f(u)du\int_a^b f(g(x))g'(x) \, dx = \int_{g(a)}^{g(b)} f(u) \, du

Step 1: Choosing uu

To simplify the integral, we let: u=5x3u = 5x - 3

Step 2: Differentiating uu

Next, we differentiate uu with respect to xx to find dudu:

du=5dxor equivalentlydx=du5du = 5 \, dx \quad \text{or equivalently} \quad dx = \frac{du}{5}

Step 3: Changing the limits of integration

The original limits of integration are from x=1x = 1 to x=4x = 4. We need to convert these limits in terms of uu.

  • When x=1x = 1: u=5(1)3=2u = 5(1) - 3 = 2
  • When x=4x = 4: u=5(4)3=17u = 5(4) - 3 = 17

So the limits of integration for uu are from 2 to 17.

Step 4: Substituting into the integral

The integral becomes:

217u5du5\int_2^{17} u^5 \cdot \frac{du}{5}

Simplifying:

15217u5du\frac{1}{5} \int_2^{17} u^5 \, du

Step 5: Solving the integral

Now we integrate u5u^5:

u5du=u66\int u^5 \, du = \frac{u^6}{6}

Thus, the integral becomes:

15[u66]217\frac{1}{5} \cdot \left[ \frac{u^6}{6} \right]_2^{17}

Step 6: Applying the limits

Substitute u=17u = 17 and u=2u = 2:

15(1766266)\frac{1}{5} \cdot \left( \frac{17^6}{6} - \frac{2^6}{6} \right)

Now, let's compute the result. I will calculate this.The value of the original integral is:

804583.5804583.5

Here’s a summary of the u-substitution steps:

  • u=5x3u = 5x - 3
  • du=5dxdu = 5 \, dx, so dx=du5dx = \frac{du}{5}
  • Limits for uu go from 2 to 17
  • The integral simplifies to 15217u5du\frac{1}{5} \int_2^{17} u^5 \, du
  • The computed result is 804583.5804583.5

Would you like further clarification on any of the steps, or do you have additional questions?

5 Related Questions:

  1. How does u-substitution simplify complex integrals?
  2. Why do we need to adjust the limits when performing u-substitution?
  3. Can u-substitution be applied to any integral?
  4. What happens if you forget to change the limits during substitution?
  5. What is the significance of the constant factor when substituting dudu?

Tip:

Always check if you need to adjust the limits of integration after making a substitution. This is a common point where errors can occur in definite integrals.

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Math Problem Analysis

Mathematical Concepts

Calculus
Integration
u-substitution

Formulas

u = g(x)
du/dx = g'(x)
dx = du / g'(x)
∫ f(g(x)) g'(x) dx = ∫ f(u) du

Theorems

Fundamental Theorem of Calculus
Chain Rule

Suitable Grade Level

Grades 11-12, Early College