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The given integral is:

\[
\int - (12x + 4)(4 - (3x^2 + 2x))^5 \, dx
\]

### Steps to solve the integral:

1. **Substitution**:
   Let:
   \[
   u = 4 - (3x^2 + 2x)
   \]
   Then, differentiate \(u\) with respect to \(x\):
   \[
   \frac{du}{dx} = -(6x + 2)
   \]
   Hence, 
   \[
   du = -(6x + 2) \, dx
   \]
   Notice that the factor \((12x + 4)\) can be factored as:
   \[
   12x + 4 = 2(6x + 2)
   \]
   This matches the derivative of \(u\), which simplifies the integral.

2. **Substitute into the integral**:
   Rewriting the integral in terms of \(u\):
   \[
   \int - (12x + 4)(4 - (3x^2 + 2x))^5 \, dx = \int - 2(6x + 2) u^5 \, dx
   \]
   Since \(du = -(6x + 2) dx\), we have:
   \[
   \int -2(6x + 2) u^5 \, dx = \int 2 u^5 \, du
   \]

3. **Integrate**:
   Now, integrate with respect to \(u\):
   \[
   \int 2 u^5 \, du = \frac{2}{6+1} u^{6} = \frac{2}{7} u^6 + C
   \]

4. **Substitute back \(u = 4 - (3x^2 + 2x)\)**:
   Finally, substitute back the expression for \(u\):
   \[
   \frac{2}{7} \left(4 - (3x^2 + 2x)\right)^6 + C
   \]

Thus, the solution to the integral is:

\[
\frac{2}{7} \left(4 - (3x^2 + 2x)\right)^6 + C
\]

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Would you like more details on any step, or do you have any further questions?

Here are some related questions to consider:
1. What is the significance of substitution in integration?
2. How would the result change if the exponent inside the integral was different?
3. Can integration by parts be used here instead of substitution?
4. How would the integration process change if \( (12x + 4) \) had a different form?
5. What are some common mistakes to watch for when applying substitution in integrals?

**Tip**: Always ensure that the differential \( du \) is fully accounted for when using substitution, as missing or incorrect terms can lead to errors.

This page provides a detailed step-by-step solution to the integral ∫ -(12x + 4)(4 - (3x^2 + 2x))^5 dx using the substitution method. The solution covers key calculus concepts and demonstrates how to apply the substitution rule effectively. Ideal for advanced high school or college-level students.

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