Math Problem Statement

placebo N=23, Mean=8.1, stdev=1.8. Zinc N=25, Mean=4.5, stdev=1.6

Solution

To compare the placebo and zinc groups, we can perform a two-sample t-test to determine if the difference in means is statistically significant. Here’s a breakdown of the calculation:

Step 1: Define Hypotheses

  1. Null Hypothesis (H0): There is no difference in means between the placebo and zinc groups (μplacebo=μzinc\mu_{placebo} = \mu_{zinc}).
  2. Alternative Hypothesis (H1): There is a difference in means between the placebo and zinc groups (μplaceboμzinc\mu_{placebo} \neq \mu_{zinc}).

Step 2: Calculate the Test Statistic

For a two-sample t-test, the formula for the test statistic tt is: t=Xˉ1Xˉ2s12N1+s22N2t = \frac{\bar{X}_1 - \bar{X}_2}{\sqrt{\frac{s_1^2}{N_1} + \frac{s_2^2}{N_2}}} where:

  • Xˉ1=8.1\bar{X}_1 = 8.1 (mean of placebo)
  • Xˉ2=4.5\bar{X}_2 = 4.5 (mean of zinc)
  • s1=1.8s_1 = 1.8 (standard deviation of placebo)
  • s2=1.6s_2 = 1.6 (standard deviation of zinc)
  • N1=23N_1 = 23 (sample size of placebo)
  • N2=25N_2 = 25 (sample size of zinc)

Calculation:

  1. Difference in means: Xˉ1Xˉ2=8.14.5=3.6\bar{X}_1 - \bar{X}_2 = 8.1 - 4.5 = 3.6

  2. Pooled standard error: SE=1.8223+1.6225=3.2423+2.5625\text{SE} = \sqrt{\frac{1.8^2}{23} + \frac{1.6^2}{25}} = \sqrt{\frac{3.24}{23} + \frac{2.56}{25}}

  3. Calculate each part:

    • 3.24230.1409\frac{3.24}{23} \approx 0.1409
    • 2.56250.1024\frac{2.56}{25} \approx 0.1024
  4. Total standard error: SE=0.1409+0.1024=0.24330.4933\text{SE} = \sqrt{0.1409 + 0.1024} = \sqrt{0.2433} \approx 0.4933

  5. t-value: t=3.60.49337.30t = \frac{3.6}{0.4933} \approx 7.30

Step 3: Determine Degrees of Freedom

Using the Satterthwaite approximation for degrees of freedom dfdf: df(s12N1+s22N2)2(s12N1)2N11+(s22N2)2N21df \approx \frac{\left(\frac{s_1^2}{N_1} + \frac{s_2^2}{N_2}\right)^2}{\frac{\left(\frac{s_1^2}{N_1}\right)^2}{N_1 - 1} + \frac{\left(\frac{s_2^2}{N_2}\right)^2}{N_2 - 1}}

Substituting values will yield an approximate dfdf. We then compare our tt-value to the critical value or obtain a pp-value to assess significance.

Would you like a detailed continuation with exact degrees of freedom, or interpretation based on a p-value approach?


  1. What is the significance level (e.g., 0.05 or 0.01) you’d like for this test?
  2. Are you interested in one-sided or two-sided test results?
  3. Would you like further explanation on the Satterthwaite approximation?
  4. How would we interpret a significant result in this context?
  5. Would you like to see this calculated using Python or statistical software?

Tip: When comparing two groups, checking assumptions like normality and equal variances can strengthen the validity of a t-test.

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Math Problem Analysis

Mathematical Concepts

Statistics
Hypothesis Testing
Two-sample t-test

Formulas

t = (X̄₁ - X̄₂) / √((s₁² / N₁) + (s₂² / N₂))
Degrees of freedom approximation: df ≈ [(s₁² / N₁ + s₂² / N₂)²] / [(s₁² / N₁)² / (N₁ - 1) + (s₂² / N₂)² / (N₂ - 1)]

Theorems

Satterthwaite approximation for degrees of freedom
Two-sample t-test for comparing means

Suitable Grade Level

Undergraduate Statistics