Math Problem Statement

Construct a truth table for ∼ q → ∼ p. Use T for true and F for false.

Solution

The statement given in the image is:

Construct a truth table for qp\sim q \rightarrow \sim p. Use T for true and F for false.

Here:

  • q\sim q represents the negation of qq,
  • p\sim p represents the negation of pp,
  • \rightarrow is the implication operator ("if... then...").

Let's break it down and construct the truth table step-by-step.

ppqqp\sim pq\sim qqp\sim q \rightarrow \sim p
TTFFT
TFFTF
FTTFT
FFTTT

Explanation:

  1. pp and qq take all combinations of True (T) and False (F).
  2. p\sim p is the negation of pp, and q\sim q is the negation of qq.
  3. The implication qp\sim q \rightarrow \sim p evaluates to False only when q\sim q is True and p\sim p is False, and True in all other cases.

Would you like more detailed reasoning or explanations on any particular step?

Follow-up Questions:

  1. What does the implication \rightarrow represent in logic?
  2. How does negation affect the truth values of propositions?
  3. Can you apply this truth table to a real-world scenario involving conditions pp and qq?
  4. How would the truth table change if the operator were \leftrightarrow (biconditional)?
  5. Can you extend this truth table to include three variables (e.g., p,q,rp, q, r)?

Tip:

When constructing truth tables, always start by listing all possible combinations of truth values for the variables involved.

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Math Problem Analysis

Mathematical Concepts

Logic
Propositional Logic
Truth Tables

Formulas

Implication: p → q
Negation: ∼ p

Theorems

Truth table rules
Implication rules in logic

Suitable Grade Level

Grades 9-12