To solve this problem, we need to break it down step by step. We are given the following information:

1. Position of point A:

   • Point A is 15 mm above the Horizontal Plane (H.P.).
   • Point A is 25 mm in front of the Vertical Plane (V.P.).

2. Angle made by the line AB with H.P.:

   • The line AB makes an angle of 20° with the H.P.

3. Length of the line in the Top View (T.V.):

   • The length of the projection of line AB on the top view (T.V.) is 90 mm.

4. Position of point B:

   • Point B is equidistant from both the principal planes (H.P. and V.P.). This means the distance of point B from both H.P. and V.P. is the same.

Solution

Step 1: Understanding the projections

• The top view of the line (T.V.) gives the horizontal projection of the line. The length of this horizontal projection is 90 mm.
• The front view of the line (F.V.) will give the vertical projection, which depends on the angle made by the line with H.P.

Step 2: True length of the line

The true length (TL) of the line can be determined using the relationship between the length of the top view (horizontal projection) and the angle the line makes with the H.P.

We can use the formula:

$TL = \frac{l_{TV}}{\cos(\theta)}$

where:

• $TL$ = True length of the line
• $l_{TV}$ = Length of the line in the top view = 90 mm
• $\theta$ = Angle with the H.P. = 20°

Substitute the values:

$TL = \frac{90}{\cos(20^\circ)}$

First, calculate the cosine of 20°:

$\cos(20^\circ) \approx 0.9397$

Now, calculate the true length:

$TL = \frac{90}{0.9397} \approx 95.77 \text{ mm}$

So, the true length of the line is approximately 95.77 mm.

Step 3: Angle with the Vertical Plane (V.P.)

To find the angle made by the line with the V.P. (denote this angle as $\phi$), we use the fact that we know the horizontal and vertical projections.

Using the right triangle relationship for the angle with the V.P., we can use:

$\sin(\phi) = \frac{\text{vertical projection}}{TL}$

The vertical projection is given by the height difference between points A and B in the front view (related to the distance of B from the H.P. and V.P.).

Since point B is equidistant from both planes, and point A is 15 mm above the H.P., the vertical projection from A to B must also be related to the true length of the line.

From this, we can compute $\phi$.

Step 4: Summarizing the results

• The true length of the line is approximately 95.77 mm.
• The angle with the V.P. can be further calculated based on the equidistance condition.

Would you like to proceed with additional clarifications on finding the exact angle with the V.P.?

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Related Questions:

1. How can we calculate the true length if the angle with V.P. is known instead of H.P.?
2. What would the projection length on the front view (F.V.) be?
3. How does the angle of a line with one plane affect its projection on the other plane?
4. What is the significance of equidistance from H.P. and V.P. for point B?
5. How would the calculation change if the angle with H.P. were 45° instead of 20°?

Tip:

To accurately visualize and solve problems involving projections, always break down the 3D geometry into its 2D views (Top View, Front View) and use trigonometry.