Math Problem Statement

csc(21°)=sec(___°)

Solution

The equation csc(21)=sec(θ)\csc(21^\circ) = \sec(\theta^\circ) can be solved by understanding the relationship between cosecant and secant. The cosecant function is the reciprocal of the sine function, and the secant function is the reciprocal of the cosine function. We need to find the angle θ\theta such that:

csc(21)=sec(θ)\csc(21^\circ) = \sec(\theta^\circ)

This implies that:

sin(21)=cos(θ)\sin(21^\circ) = \cos(\theta^\circ)

Using the identity sin(θ)=cos(90θ)\sin(\theta) = \cos(90^\circ - \theta), we can see that:

θ=9021=69\theta^\circ = 90^\circ - 21^\circ = 69^\circ

Thus,

csc(21)=sec(69)\csc(21^\circ) = \sec(69^\circ)

Would you like more details or have any questions?

Here are 5 related questions for further exploration:

  1. What is the general relationship between the secant and cosecant functions?
  2. How do you convert between sine and cosine for complementary angles?
  3. What is the value of csc(21)\csc(21^\circ) approximately?
  4. How does the identity sin(θ)=cos(90θ)\sin(\theta) = \cos(90^\circ - \theta) apply to other angles?
  5. How can trigonometric identities simplify solving equations?

Tip: When dealing with complementary angles, remember that sin(θ)=cos(90θ)\sin(\theta) = \cos(90^\circ - \theta) and vice versa.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Reciprocal Functions
Complementary Angles

Formulas

csc(θ) = 1/sin(θ)
sec(θ) = 1/cos(θ)
sin(θ) = cos(90° - θ)

Theorems

Complementary Angle Identity

Suitable Grade Level

Grades 9-12