Math Problem Statement

(1 - sin^2A)(1 + cot^2A) = cot^2A

Solution

Let's solve the equation from the image:

(1sin2A)(1+cot2A)=cot2A(1 - \sin^2 A)(1 + \cot^2 A) = \cot^2 A

Step-by-step solution:

  1. Recognize an identity: Notice that 1sin2A1 - \sin^2 A can be replaced using the Pythagorean identity: 1sin2A=cos2A1 - \sin^2 A = \cos^2 A So the equation becomes: cos2A(1+cot2A)=cot2A\cos^2 A \cdot (1 + \cot^2 A) = \cot^2 A

  2. Substitute the definition of cot2A\cot^2 A: Recall that: cot2A=cos2Asin2A\cot^2 A = \frac{\cos^2 A}{\sin^2 A} Now substitute cot2A\cot^2 A into the equation: cos2A(1+cos2Asin2A)=cos2Asin2A\cos^2 A \cdot \left(1 + \frac{\cos^2 A}{\sin^2 A}\right) = \frac{\cos^2 A}{\sin^2 A}

  3. Simplify the expression inside the parentheses: Combine the terms inside the parentheses: 1+cos2Asin2A=sin2A+cos2Asin2A1 + \frac{\cos^2 A}{\sin^2 A} = \frac{\sin^2 A + \cos^2 A}{\sin^2 A} Using the Pythagorean identity sin2A+cos2A=1\sin^2 A + \cos^2 A = 1, this simplifies to: 1sin2A\frac{1}{\sin^2 A}

  4. Simplify the overall expression: Now the equation becomes: cos2A1sin2A=cos2Asin2A\cos^2 A \cdot \frac{1}{\sin^2 A} = \frac{\cos^2 A}{\sin^2 A} Which simplifies to: cos2Asin2A=cos2Asin2A\frac{\cos^2 A}{\sin^2 A} = \frac{\cos^2 A}{\sin^2 A}

Since both sides of the equation are equal, the given equation is verified.


Do you have any questions about the solution or would you like more details on any step? Here are some related questions to consider:

  1. What are the key Pythagorean identities in trigonometry?
  2. How do you derive the cotangent function from sine and cosine?
  3. Can this type of trigonometric verification be applied to other identities?
  4. How can you simplify trigonometric expressions involving multiple identities?
  5. How do the sine and cosine functions relate to each other geometrically on the unit circle?

Tip: Remember that using identities is a key tool in simplifying trigonometric equations.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Trigonometric Identities

Formulas

1 - sin^2A = cos^2A (Pythagorean Identity)
cot^2A = cos^2A / sin^2A

Theorems

Pythagorean Identity

Suitable Grade Level

Grades 9-12