Math Problem Statement

The sides of triangle ABC have lengths AB = 7 BC = 6 and CA = 8. CP and CQ are , respectively, the interior and the exterior angle bisectors of the triangle at vertex C. Find the lengths of segments AP, BP, AQ and PQ

Solution

We are given a triangle ABCABC with side lengths AB=7AB = 7, BC=6BC = 6, and CA=8CA = 8. The angle bisectors CPCP and CQCQ are drawn at vertex CC, where CPCP is the interior angle bisector and CQCQ is the exterior angle bisector. We need to find the lengths of segments APAP, BPBP, AQAQ, and PQPQ.

Step 1: Use the Angle Bisector Theorem for APAP and BPBP

For the interior angle bisector CPCP, we apply the Angle Bisector Theorem, which states that the interior angle bisector divides the opposite side into segments proportional to the adjacent sides. Thus, we have:

APBP=ACBC=86=43\frac{AP}{BP} = \frac{AC}{BC} = \frac{8}{6} = \frac{4}{3}

Let AP=4xAP = 4x and BP=3xBP = 3x. Since AP+BP=AB=7AP + BP = AB = 7, we can set up the following equation:

4x+3x=74x + 3x = 7

Solving for xx:

7x=7    x=17x = 7 \implies x = 1

Thus, the lengths of APAP and BPBP are:

AP=4×1=4andBP=3×1=3AP = 4 \times 1 = 4 \quad \text{and} \quad BP = 3 \times 1 = 3

Step 2: Use the Extended Angle Bisector Theorem for AQAQ and BQBQ

For the exterior angle bisector CQCQ, we use the Extended Angle Bisector Theorem, which states that the exterior angle bisector divides the opposite side into segments such that:

AQBQ=ACBC=86=43\frac{AQ}{BQ} = \frac{AC}{BC} = \frac{8}{6} = \frac{4}{3}

Let AQ=4yAQ = 4y and BQ=3yBQ = 3y. Since AQBQ=AB=7AQ - BQ = AB = 7 for the exterior angle bisector, we set up the following equation:

4y3y=74y - 3y = 7

Solving for yy:

y=7y = 7

Thus, the lengths of AQAQ and BQBQ are:

AQ=4×7=28andBQ=3×7=21AQ = 4 \times 7 = 28 \quad \text{and} \quad BQ = 3 \times 7 = 21

Step 3: Find the length of PQPQ

Since PP and QQ lie on opposite sides of BCBC, the length of PQPQ can be found using the formula:

PQ=2ABACBCsAB+ACPQ = \frac{2 \sqrt{AB \cdot AC \cdot BC \cdot s}}{AB + AC}

where ss is the semi-perimeter of the triangle. Let me calculate that for you next.The length of segment PQPQ is approximately 7.927.92.

Final Results:

  • AP=4AP = 4
  • BP=3BP = 3
  • AQ=28AQ = 28
  • PQ7.92PQ \approx 7.92

Would you like further details or have any questions about this process?

Here are 5 related questions to extend your understanding:

  1. How does the Angle Bisector Theorem apply to other types of triangles (e.g., isosceles)?
  2. What is the relationship between interior and exterior angle bisectors in a triangle?
  3. How do you derive the formula for the length of segment PQPQ in this context?
  4. Can you use this method to find the lengths of segments if one of the sides is unknown?
  5. How does this problem change if the triangle is not scalene?

Tip: The angle bisector theorem holds regardless of the type of triangle (scalene, isosceles, etc.), as long as you're bisecting the angle.

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Math Problem Analysis

Mathematical Concepts

Geometry
Angle Bisectors
Proportions

Formulas

Angle Bisector Theorem: AP/BP = AC/BC
Extended Angle Bisector Theorem: AQ/BQ = AC/BC
PQ Formula: PQ = (2 * sqrt(AB * AC * BC * s)) / (AB + AC)

Theorems

Angle Bisector Theorem
Extended Angle Bisector Theorem

Suitable Grade Level

Grades 9-12