Math Problem Statement

Solve the following problems: 10. If \(\triangle ABC\) is equilateral, solve for \(x\). 11. If \(\triangle RST\) is isosceles, find \(m\angle S\). 12. In \(\triangle PQR\), if \(m\angle P\) is 14 less than five times \(x\), \(m\angle Q\) is five less than \(x\), and \(m\angle R\) is nine less than twice \(x\), find \(x\) and the measure of each angle.

Solution

Let's go through each question one by one.

Problem 10

Given:

  • ABC\triangle ABC is equilateral, meaning all angles are 6060^\circ.
  • C=8x44\angle C = 8x - 44.

Since C=60\angle C = 60^\circ, we set up the equation: 8x44=608x - 44 = 60 Solving for xx:

  1. Add 4444 to both sides: 8x=1048x = 104
  2. Divide by 88: x=13x = 13

Problem 11

Given:

  • RST\triangle RST is isosceles, meaning two angles are equal.
  • R=15x31\angle R = 15x - 31 and T=9x+11\angle T = 9x + 11.

In an isosceles triangle, if two angles are equal, then the third angle can be calculated using the triangle angle sum property. Assume that R=T\angle R = \angle T.

Setting up the equation: 15x31=9x+1115x - 31 = 9x + 11 Solving for xx:

  1. Subtract 9x9x from both sides: 6x31=116x - 31 = 11
  2. Add 3131 to both sides: 6x=426x = 42
  3. Divide by 66: x=7x = 7

Now, substitute x=7x = 7 to find mSm\angle S: mR=15(7)31=10531=74m\angle R = 15(7) - 31 = 105 - 31 = 74^\circ mT=9(7)+11=63+11=74m\angle T = 9(7) + 11 = 63 + 11 = 74^\circ

Since R=T\angle R = \angle T, we calculate S\angle S as: mS=1807474=32m\angle S = 180^\circ - 74^\circ - 74^\circ = 32^\circ

Problem 12

Given:

  • mP=14m\angle P = 14 less than five times xx: mP=5x14m\angle P = 5x - 14.
  • mQ=5m\angle Q = 5 less than xx: mQ=x5m\angle Q = x - 5.
  • mR=9m\angle R = 9 less than twice xx: mR=2x9m\angle R = 2x - 9.

Using the triangle angle sum property: mP+mQ+mR=180m\angle P + m\angle Q + m\angle R = 180 Substitute the expressions: (5x14)+(x5)+(2x9)=180(5x - 14) + (x - 5) + (2x - 9) = 180 Combine terms: 8x28=1808x - 28 = 180 Add 2828 to both sides: 8x=2088x = 208 Divide by 88: x=26x = 26

Now, substitute x=26x = 26 to find each angle: mP=5(26)14=13014=116m\angle P = 5(26) - 14 = 130 - 14 = 116^\circ mQ=265=21m\angle Q = 26 - 5 = 21^\circ mR=2(26)9=529=43m\angle R = 2(26) - 9 = 52 - 9 = 43^\circ


Summary of Solutions

  1. Problem 10: x=13x = 13
  2. Problem 11: mS=32m\angle S = 32^\circ
  3. Problem 12: x=26x = 26, mP=116m\angle P = 116^\circ, mQ=21m\angle Q = 21^\circ, mR=43m\angle R = 43^\circ

Would you like further details on any of these problems, or do you have any questions?


Related Questions

  1. How would the solution change if ABC\triangle ABC in Problem 10 was not equilateral?
  2. Can you solve for xx in an isosceles triangle where one angle expression is given?
  3. How do you verify that two angles in a triangle are equal if it’s not specified?
  4. What other properties of triangles are useful for solving angle-related problems?
  5. How would you solve if R\angle R and S\angle S were equal instead in Problem 11?

Tip

Always double-check the properties of the triangle (isosceles, equilateral, etc.) as they provide key insights for setting up equations.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Triangle Properties
Equilateral Triangle
Isosceles Triangle
Algebraic Equations

Formulas

Sum of angles in a triangle = 180°

Theorems

Triangle Angle Sum Theorem

Suitable Grade Level

Grades 8-10