The given question is in Marathi, and it asks:

In a triangle, the three angles are in the ratio 1:2:3. What is the measure of the smallest angle?

Solution:

The sum of all angles in any triangle is always $180^\circ$. Let's assume the angles are $x$, $2x$, and $3x$ (since they are in the ratio 1:2:3).

So, the equation is: $x + 2x + 3x = 180^\circ$ $6x = 180^\circ$ $x = \frac{180^\circ}{6} = 30^\circ$

Thus, the smallest angle is $30^\circ$.

Correct Option:

The correct answer is C. 30

Would you like more details on the solution or any further clarifications? Here are 5 related questions for practice:

1. If the angles of a triangle are in the ratio 2:3:5, what is the smallest angle?
2. What is the largest angle in a triangle with angles in the ratio 1:4:5?
3. If one angle of a triangle is $45^\circ$ and the other two are in the ratio 3:4, what are the other two angles?
4. In a right-angled triangle, if one of the angles is $30^\circ$, what is the other angle?
5. Can a triangle have angles in the ratio 1:1:4?

Tip: Always remember that the sum of interior angles of any triangle is $180^\circ$.