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The given question is in Marathi, and it asks:

*In a triangle, the three angles are in the ratio 1:2:3. What is the measure of the smallest angle?*

### Solution:

The sum of all angles in any triangle is always \(180^\circ\). Let's assume the angles are \(x\), \(2x\), and \(3x\) (since they are in the ratio 1:2:3).

So, the equation is:
\[
x + 2x + 3x = 180^\circ
\]
\[
6x = 180^\circ
\]
\[
x = \frac{180^\circ}{6} = 30^\circ
\]

Thus, the smallest angle is \(30^\circ\).

### Correct Option:
The correct answer is **C. 30**

Would you like more details on the solution or any further clarifications? Here are 5 related questions for practice:

1. If the angles of a triangle are in the ratio 2:3:5, what is the smallest angle?
2. What is the largest angle in a triangle with angles in the ratio 1:4:5?
3. If one angle of a triangle is \(45^\circ\) and the other two are in the ratio 3:4, what are the other two angles?
4. In a right-angled triangle, if one of the angles is \(30^\circ\), what is the other angle?
5. Can a triangle have angles in the ratio 1:1:4?

**Tip**: Always remember that the sum of interior angles of any triangle is \(180^\circ\).

एका त्रिकोणाचे तिन्ही कोनांचे गुणोत्तर 1:2:3 प्रमाणे आहे तर सर्वात लहान कोण किती अंशाचा असेल?

Learn how to find the smallest angle in a triangle with angles in the ratio 1:2:3. This problem covers key geometric concepts, including the sum of angles in a triangle. Suitable for students in Grades 7-8.

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