https://file.aiquickdraw.com/mathbot/file/1726117660796wlq3t3ft.jpg

The problem in the image can be solved using the torque formula. Here's how the information is interpreted:

- A 50 Newton force is applied to a bicycle pedal.
- The shaft of the pedal is 20 cm (or 0.2 meters) long.
- The angle between the shaft and the horizontal is \(\pi/3\) radians.

### Formula for Torque:
\[
\tau = r \cdot F \cdot \sin(\theta)
\]
Where:
- \(\tau\) is the torque.
- \(r\) is the length of the lever arm (shaft of the pedal).
- \(F\) is the force applied.
- \(\theta\) is the angle between the force direction and the lever arm.

### Given:
- \(r = 0.2 \, \text{m}\)
- \(F = 50 \, \text{N}\)
- \(\theta = \frac{\pi}{3} \, \text{radians}\)

Now, let's compute the torque.The magnitude of the torque is approximately \( 8.66 \, \text{Nm} \).

Would you like more details or have any further questions?

Here are some related questions to think about:
1. How would the torque change if the force applied were increased to 100 N?
2. What would happen to the torque if the pedal shaft were longer, say 30 cm?
3. How does the angle \(\theta\) affect the torque when it becomes smaller or larger than \(\pi/3\)?
4. What is the torque if the angle is \(0\) radians (i.e., when the pedal is horizontal)?
5. How can the direction of the force affect the overall efficiency in pedaling a bicycle?

**Tip**: Torque is maximized when the angle between the force and the lever arm is \(90^\circ\) or \(\frac{\pi}{2}\) radians.

A bicycle pedal is pushed straight downwards by a foot with a 50 Newton force. The shaft of the pedal is 20 cm long. If the shaft is pi/3 radians past horizontal, what is the magnitude of the torque about the point where the shaft is attached to the bicycle?

Learn how to calculate the torque exerted on a bicycle pedal when a 50 N force is applied downward, with a 20 cm pedal shaft at an angle of pi/3 radians. This physics problem uses the torque formula τ = r * F * sin(θ) and is suitable for high school students in Grades 9-12.

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