Math Problem Statement

The area of a rectangular field is 240 sq m and one of its sides is 10 m. How long will it take to cross the field diagonally at the rate of 25 m/minute?

Solution

Let’s solve this step-by-step:

Problem Analysis:

  1. Given:

    • The area of the rectangular field = 240 m².
    • One side of the rectangle = 10 m.
    • Speed of crossing diagonally = 25 m/minute.
  2. Find:

    • The time it takes to cross the field diagonally.

Step 1: Find the dimensions of the rectangle.

The formula for the area of a rectangle is: Area=length×width\text{Area} = \text{length} \times \text{width} Here, one side (width) is given as 10 m, so: length=Areawidth=24010=24m.\text{length} = \frac{\text{Area}}{\text{width}} = \frac{240}{10} = 24 \, \text{m.} Thus, the dimensions of the rectangle are 10 m × 24 m.


Step 2: Calculate the diagonal of the rectangle.

The diagonal (dd) of a rectangle can be calculated using the Pythagorean theorem: d=(length)2+(width)2d = \sqrt{(\text{length})^2 + (\text{width})^2} Substitute length=24m\text{length} = 24 \, \text{m} and width=10m\text{width} = 10 \, \text{m}: d=242+102=576+100=676=26m.d = \sqrt{24^2 + 10^2} = \sqrt{576 + 100} = \sqrt{676} = 26 \, \text{m.}


Step 3: Time to cross the field diagonally.

The time (tt) it takes to cross the diagonal is: t=distancespeedt = \frac{\text{distance}}{\text{speed}} Substitute distance=26m\text{distance} = 26 \, \text{m} and speed=25m/min\text{speed} = 25 \, \text{m/min}: t=2625=1.04minutes.t = \frac{26}{25} = 1.04 \, \text{minutes.}


Final Answer:

It will take approximately 1.04 minutes (or 62.4 seconds) to cross the field diagonally.


Would you like further details or explanations?

Related Questions:

  1. How do you calculate the diagonal of any rectangular shape?
  2. What is the relationship between area and perimeter in a rectangle?
  3. How would the time change if the speed was halved?
  4. What is the significance of the Pythagorean theorem in geometry?
  5. How do you convert time in decimals (e.g., 1.04 minutes) into minutes and seconds?

Tip:

When solving problems involving geometry, always draw a quick diagram to help visualize the relationships between the given values.

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Math Problem Analysis

Mathematical Concepts

Geometry
Area of a Rectangle
Diagonal Calculation
Rate and Time

Formulas

Area = length × width
Diagonal = √(length² + width²)
Time = distance ÷ speed

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 6-8