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The problem states that in Week 1, five times as many tickets were sold as the combined number of tickets sold in Weeks 2 and 3. We're tasked with finding how many tickets were sold in Week 1.

### Given:
- **Week 2**: 432 tickets
- **Week 3**: 117 tickets

Let the number of tickets sold in Week 1 be denoted by $ x $.

From the problem, we know:
\[
x = 5 \times (\text{Week 2} + \text{Week 3})
\]
Substituting the values for Week 2 and Week 3:
\[
x = 5 \times (432 + 117)
\]
\[
x = 5 \times 549 = 2745
\]

### Conclusion:
The number of tickets sold in **Week 1** is 2,745.

Do you want more details or have any questions?

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Here are 5 related questions for further practice:
1. What would the total number of tickets sold over all three weeks be?
2. If Week 1 sold 10% more tickets than planned, how many tickets were planned for Week 1?
3. If Week 3 had doubled its ticket sales, what would the new total number of tickets sold be in Weeks 2 and 3 combined?
4. If the number of tickets sold in Week 2 was reduced by 50%, what would Week 1's ticket sales need to be to maintain the 5:1 ratio?
5. If tickets in Week 3 were sold at $12 each, how much revenue did Week 3 generate?

**Tip**: When working with proportional relationships like these, always verify the total quantities involved before and after applying the ratio.

There were five times as many tickets sold in Week 1 than were sold in Weeks 2 and 3 combined. How many tickets were sold in Week 1?

This problem involves finding the number of tickets sold in Week 1, given that it is five times the combined number of tickets sold in Weeks 2 and 3. Learn how to use basic algebra to solve this problem for students in Grades 6-8.

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