
Two friends pooled the tickets they won from playing video games to get a prize that requires 600 tickets. If the first friend won 30 more tickets than the second friend, how many tickets did each friend win?

Let's denote the number of tickets won by the second friend as \( x \). 

Since the first friend won 30 more tickets than the second friend, the number of tickets won by the first friend is \( x + 30 \).

The total number of tickets pooled by both friends is 600. So, we can write the equation:

\[
x + (x + 30) = 600
\]

Now, let's solve the equation:

\[
2x + 30 = 600
\]

Subtract 30 from both sides:

\[
2x = 570
\]

Divide both sides by 2:

\[
x = 285
\]

So, the second friend won 285 tickets.

To find the number of tickets won by the first friend, we add 30 to the second friend's tickets:

\[
x + 30 = 285 + 30 = 315
\]

Therefore:
- The first friend won **315 tickets**.
- The second friend won **285 tickets**.

Would you like more details or have any questions?

Here are 5 related questions:
1. How would the solution change if the prize required 800 tickets instead?
2. What if the first friend had won 50 more tickets than the second friend?
3. How many tickets would each friend have won if they both won an equal number of tickets?
4. Can you express the solution as a system of linear equations?
5. What if the total number of tickets was unknown, but the ratio of tickets won was known?

**Tip:** When solving word problems, start by defining variables for unknowns, then set up equations based on the relationships described.

Two friends pooled the tickets they won from playing video games to get a prize that requires 600 tickets. If the first friend won 30 more tickets than the second friend, how many tickets did each friend win?

Discover how to solve a real-world algebra problem where two friends pool their tickets to get a prize. Learn how to set up and solve linear equations to find out how many tickets each friend won. This problem is suitable for students in Grades 6-8.

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