Math Problem Statement

The sum of the digits of a three-place number is 19. If the tens and units digits are interchanged the number is diminished by 27, and if the hundreds and tens digits are interchanged the number is increased by 180. What is the number?

Solution

Let's solve the problem step by step.

Step 1: Define the number

Let the three-digit number be represented as 100h+10t+u100h + 10t + u, where:

  • hh = hundreds digit,
  • tt = tens digit,
  • uu = units digit.

Step 2: Translate the given conditions

  1. The sum of the digits is 19: h+t+u=19h + t + u = 19

  2. When the tens and units digits are interchanged, the number is diminished by 27: The new number becomes 100h+10u+t100h + 10u + t. The equation is: 100h+10t+u(100h+10u+t)=27100h + 10t + u - (100h + 10u + t) = 27 Simplify: 9t9u=27tu=39t - 9u = 27 \quad \Rightarrow \quad t - u = 3

  3. When the hundreds and tens digits are interchanged, the number is increased by 180: The new number becomes 100t+10h+u100t + 10h + u. The equation is: 100t+10h+u(100h+10t+u)=180100t + 10h + u - (100h + 10t + u) = 180 Simplify: 90t90h=180th=290t - 90h = 180 \quad \Rightarrow \quad t - h = 2

Step 3: Solve the system of equations

We now have three equations:

  1. h+t+u=19h + t + u = 19
  2. tu=3t - u = 3
  3. th=2t - h = 2

From equation (3): t=h+2t = h + 2

Substitute t=h+2t = h + 2 into equation (2): h+2u=3u=h1h + 2 - u = 3 \quad \Rightarrow \quad u = h - 1

Substitute t=h+2t = h + 2 and u=h1u = h - 1 into equation (1):

h+(h+2)+(h1)=19h + (h + 2) + (h - 1) = 19 Simplify: 3h+1=193h=18h=63h + 1 = 19 \quad \Rightarrow \quad 3h = 18 \quad \Rightarrow \quad h = 6

Find tt and uu:

t=h+2=6+2=8t = h + 2 = 6 + 2 = 8 u=h1=61=5u = h - 1 = 6 - 1 = 5

Step 4: Verify the solution

The number is 100h+10t+u=100(6)+10(8)+5=685100h + 10t + u = 100(6) + 10(8) + 5 = 685.

  • Sum of digits: 6+8+5=196 + 8 + 5 = 19 (satisfied).
  • Interchanging tt and uu: 685658=27685 - 658 = 27 (satisfied).
  • Interchanging hh and tt: 865685=180865 - 685 = 180 (satisfied).

Final Answer:

The number is 685.

Do you have any questions or want further clarification? Here are five related problems to consider:

  1. What if the sum of the digits was 21 instead of 19?
  2. How would the solution change if the increase when interchanging hh and tt was 190?
  3. Can this problem be solved using matrices for the system of equations?
  4. What happens if the digits tt and uu are equal?
  5. How can such problems be represented and solved programmatically?

Tip: Always break multi-condition problems into manageable equations and solve systematically.

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Math Problem Analysis

Mathematical Concepts

Algebra
System of Linear Equations
Place Value in Numbers

Formulas

Representation of a three-digit number: 100h + 10t + u
Sum of digits: h + t + u = 19
Interchange relationships: t - u = 3, t - h = 2

Theorems

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Suitable Grade Level

Grades 8-10