Math Problem Statement
Solution
Let's solve the problem.
Let the three-digit number be represented as , where:
- is the hundreds digit,
- is the tens digit,
- is the units digit.
The problem gives us two conditions:
- The units digit is the sum of the hundreds and tens digits:
- The units digit exceeds the tens digit by as much as the tens digit exceeds the hundreds digit: This simplifies to:
Now, we have the system of equations:
Step 1: Set the two expressions for equal to each other:
Step 2: Solve for :
Add to both sides: Subtract from both sides: Thus, the tens digit .
Step 3: Substitute into the first equation for :
Step 4: Now, since , , and are digits, they must be integers between 0 and 9. Let's check possible values of :
- : , → The number is .
- : , → The number is .
- : , → The number is .
For or higher, would be 8 or higher, and would be greater than 9, which is not allowed since digits must be between 0 and 9.
Conclusion:
There are 3 such three-digit numbers: , , and .
Thus, the answer is .
Would you like more details on any step? Here are 5 related questions to further explore this topic:
- How would the solution change if the problem specified a different relationship between the digits?
- Can this method be applied to other multi-digit numbers? If so, how?
- What if the sum of the digits had to follow a different rule, such as being divisible by a certain number?
- How could the concept of modular arithmetic help in solving this type of digit problem?
- Can you find other problems where the difference between digits plays a crucial role in the solution?
Tip: When working with digit problems, always pay attention to the constraints on the values of the digits (i.e., they must be between 0 and 9).
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Math Problem Analysis
Mathematical Concepts
Algebra
Digit Properties
Equations
Formulas
c = a + b (where c is the units digit, a is the hundreds digit, and b is the tens digit)
c - b = b - a
Theorems
Equating expressions for digits
Solving systems of equations
Suitable Grade Level
Grades 8-10
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