Math Problem Statement

A three-digit number is base 10 is represented as ABC, where A,B,C are its digits The number satisfies A+B+C 12 the following conditions:

  1. A+B+C = 12

  2. When the digits A, B and c are reversed the new number CBA is exactly 594 less than the original number ABC. Determine the original number ABC?

Solution

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Math Problem Analysis

Mathematical Concepts

Algebra
Digit Manipulation
Place Value
Equation Solving

Formulas

ABC = 100A + 10B + C
CBA = 100C + 10B + A
A + B + C = 12
CBA = ABC - 594

Theorems

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Suitable Grade Level

Grades 7-10