Math Problem Statement

How many three-digit even numbers which are divisible by 11 also have the sum of their digits equal to 10?

Solution

To find the three-digit even numbers that are divisible by 11 and have the sum of their digits equal to 10, let's analyze the problem step-by-step.

Let:

  • The three-digit number be represented as abc=100a+10b+c\overline{abc} = 100a + 10b + c, where aa, bb, and cc are the hundreds, tens, and units digits respectively.
  • The conditions are:
    1. abc\overline{abc} is even, so cc must be even.
    2. abc\overline{abc} is divisible by 11.
    3. The sum of the digits a+b+c=10a + b + c = 10.

Step 1: Condition for Divisibility by 11

For a number to be divisible by 11, the alternating sum of its digits must be divisible by 11. This means: ab+c=0orab+c=11a - b + c = 0 \quad \text{or} \quad a - b + c = 11

Step 2: Finding Possible Values of aa, bb, and cc

Since abc\overline{abc} is a three-digit number, aa must be between 1 and 9. Additionally, since abc\overline{abc} is even, cc must be an even digit (0, 2, 4, 6, or 8).

We will now use both conditions to identify valid values for aa, bb, and cc such that:

  1. a+b+c=10a + b + c = 10
  2. ab+c=0a - b + c = 0 (since ab+c=11a - b + c = 11 would exceed the digit constraint)

Step 3: Solving the Equations

Using the system: a+b+c=10a + b + c = 10 ab+c=0a - b + c = 0

Add the two equations: 2a+2c=10    a+c=52a + 2c = 10 \implies a + c = 5

Substitute a+c=5a + c = 5 back into the first equation: a+b+c=10    5+b=10    b=5a + b + c = 10 \implies 5 + b = 10 \implies b = 5

Thus, we have:

  1. b=5b = 5
  2. a+c=5a + c = 5

Now, we examine possible pairs (a,c)(a, c) where a+c=5a + c = 5 and cc is even:

  • a=1a = 1, c=4c = 4
  • a=3a = 3, c=2c = 2
  • a=5a = 5, c=0c = 0

Step 4: Constructing the Numbers

The possible three-digit numbers abc\overline{abc} that meet all conditions are:

  • 154154 (with a=1a = 1, b=5b = 5, c=4c = 4)
  • 352352 (with a=3a = 3, b=5b = 5, c=2c = 2)
  • 550550 (with a=5a = 5, b=5b = 5, c=0c = 0)

Step 5: Verification

Each of these numbers:

  1. Is even.
  2. Has digits summing to 10.
  3. Is divisible by 11.

Therefore, there are 3 such numbers: 154, 352, and 550.

Final Answer

There are 3 three-digit even numbers that are divisible by 11 and have the sum of their digits equal to 10.

Would you like a more detailed breakdown or have any questions about the steps?


  1. How would the solution change if the sum of the digits were 12 instead of 10?
  2. Can this method be applied to four-digit numbers, and what modifications would be needed?
  3. What would the solution be if the numbers had to be odd instead of even?
  4. How would the solution differ if we considered divisibility by another number, like 7?
  5. How can we generalize this method to find numbers with different divisibility and sum conditions?

Tip: Always check conditions one by one to simplify complex constraints.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Divisibility Rules
Digit Sum Constraints

Formulas

Three-digit number representation: 100a + 10b + c
Sum of digits: a + b + c = 10
Divisibility rule for 11: a - b + c = 0 or a - b + c = 11

Theorems

Divisibility Rule for 11

Suitable Grade Level

Grades 9-10