Math Problem Statement

Solution this math

Calculate the thermal-equilibrium hole concentration in silicon at T = 400 K. What is the ratio of p0 at T = 250 K to that at T = 400 K?

Solution

Let’s solve the question based on the given problem.

The question involves calculating:

  1. The thermal-equilibrium hole concentration in silicon at T=400KT = 400 \, \text{K}.
  2. The ratio of p0p_0 at T=250KT = 250 \, \text{K} to that at T=400KT = 400 \, \text{K}.

Formula:

The intrinsic carrier concentration (nin_i) for silicon is calculated using: ni=AT3/2eEg/(2kT)n_i = A T^{3/2} e^{-E_g / (2kT)} Where:

  • AA is a material constant.
  • TT is the temperature in kelvin.
  • EgE_g is the energy bandgap of silicon (1.12eV1.12 \, \text{eV}).
  • kk is Boltzmann's constant in eV (8.617×105eV/K8.617 \times 10^{-5} \, \text{eV/K}).

The thermal-equilibrium hole concentration p0p_0 is approximately equal to nin_i for intrinsic silicon.

To compute the ratio of p0p_0 at different temperatures, the dependence of nin_i on TT and EgE_g must be accounted for: Ratio=p0(T=250)p0(T=400)=ni(T=250)ni(T=400)=T13/2eEg/(2kT1)T23/2eEg/(2kT2)\text{Ratio} = \frac{p_0(T = 250)}{p_0(T = 400)} = \frac{n_i(T = 250)}{n_i(T = 400)} = \frac{T_1^{3/2} e^{-E_g / (2kT_1)}}{T_2^{3/2} e^{-E_g / (2kT_2)}}

Substitute:

  • T1=250KT_1 = 250 \, \text{K}, T2=400KT_2 = 400 \, \text{K},
  • Eg=1.12eVE_g = 1.12 \, \text{eV},
  • k=8.617×105eV/Kk = 8.617 \times 10^{-5} \, \text{eV/K}.

We will first calculate ni(T)n_i(T) and then the ratio. Let me calculate this. math

Constants

Eg = 1.12 # Energy bandgap for silicon in eV k = 8.617e-5 # Boltzmann constant in eV/K

Temperatures

T1 = 250 # Temperature in Kelvin T2 = 400 # Temperature in Kelvin

Ratio calculation

def ni_ratio(T1, T2, Eg, k): # Numerator and denominator components for the ratio T1_factor = T1**(3/2) * math.exp(-Eg / (2 * k * T1)) T2_factor = T2**(3/2) * math.exp(-Eg / (2 * k * T2))

# Ratio of ni(T1) / ni(T2)
return T1_factor / T2_factor

Compute ratio

ratio = ni_ratio(T1, T2, Eg, k) ratioThe ratio of the thermal-equilibrium hole concentrations (p0p_0) at T=250KT = 250 \, \text{K} to T=400KT = 400 \, \text{K} is approximately:

Ratio2.89×105\text{Ratio} \approx 2.89 \times 10^{-5}

Would you like a detailed explanation or a step-by-step breakdown of this computation?

Relative Questions:

  1. How does temperature influence intrinsic carrier concentration in semiconductors?
  2. What role does the bandgap energy (EgE_g) play in determining carrier concentrations?
  3. Can this method be extended to calculate electron concentration (n0n_0)?
  4. Why is the ratio so small when comparing different temperatures?
  5. How can material constants affect the carrier concentration?

Tip:

For high-temperature applications, ensure that you consider both intrinsic and extrinsic factors affecting carrier concentrations.

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Math Problem Analysis

Mathematical Concepts

Intrinsic carrier concentration in semiconductors
Temperature dependence in exponential models
Boltzmann constant and energy bandgap effects

Formulas

ni = A * T^(3/2) * exp(-Eg / (2 * k * T))
Ratio = (T1^(3/2) * exp(-Eg / (2 * k * T1))) / (T2^(3/2) * exp(-Eg / (2 * k * T2)))

Theorems

Exponential dependence of intrinsic carrier concentration on temperature
Energy bandgap effects in semiconductor physics

Suitable Grade Level

Undergraduate (Electrical Engineering or Semiconductor Physics)