To determine the tension at the top end of Rope 2, let's break down the forces involved in the system:

• Let the mass of Block A be $m_A$, and the mass of Block B be $m_B$.
• The upward force $F$ is applied to Block A, and the two blocks are connected by ropes as shown in the image.

Step-by-Step Breakdown:

1. Forces on Block B:

   • Block B is hanging from Rope 2, and only its weight contributes to the tension in Rope 2.
   • The force acting on Block B is due to gravity, which is its weight $m_B g$, where $g$ is the acceleration due to gravity.

2. Tension in Rope 2 (at its top end):

   • The top end of Rope 2 supports the weight of Block B.
   • Therefore, the tension at the top end of Rope 2 is equal to the weight of Block B, which is $T_2 = m_B g$.

Final Answer:

The tension at the top end of Rope 2 is $T_2 = m_B g$, where $m_B$ is the mass of Block B, and $g$ is the acceleration due to gravity.

Would you like to discuss more details, or do you have specific values for $m_A$, $m_B$, or $F$?

Additional Questions:

1. What would the tension in Rope 1 be if the system is accelerating upwards?
2. How does the force $F$ affect the tension in both ropes?
3. What is the net force acting on Block A and Block B together?
4. If Block A and Block B have equal masses, how would that change the tension in Rope 2?
5. What happens to the tension in Rope 2 if there is no external force $F$ applied?

Tip: Always consider the forces acting on each block separately when dealing with tension in connected systems.