Math Problem Statement

A mobile at the art museum has a 2.0 kg steel cat and a 4.0 kg steel dog suspended from a lightweight cable. It is found that θ1 = 29 ∘ when the center rope is adjusted to be perfectly horizontal. What is the tension in the rope 3?

Solution

To solve this problem, we'll analyze the forces involved and apply equilibrium conditions, since the mobile is in static equilibrium. The goal is to find the tension in rope 3, which we'll denote as T3T_3.

Step-by-step approach:

  1. Free-Body Diagram Analysis:

    • There are three ropes involved:
      • Rope 1: Supporting the 2.0 kg steel cat, at an angle θ1=29\theta_1 = 29^\circ.
      • Rope 2: Supporting the 4.0 kg steel dog, at an unknown angle θ2\theta_2.
      • Rope 3: The center rope, which is perfectly horizontal, has the tension T3T_3 we need to find.
  2. Forces Acting on Each Object:

    • The force due to gravity on the steel cat is: Fcat=mcatg=2.0kg9.8m/s2=19.6NF_{\text{cat}} = m_{\text{cat}} \cdot g = 2.0 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 = 19.6 \, \text{N}
    • The force due to gravity on the steel dog is: Fdog=mdogg=4.0kg9.8m/s2=39.2NF_{\text{dog}} = m_{\text{dog}} \cdot g = 4.0 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 = 39.2 \, \text{N} These weights act vertically downward.
  3. Equilibrium Conditions:

    • In the horizontal direction, the horizontal components of the tensions must balance out: T1cos(θ1)=T2cos(θ2)T_1 \cdot \cos(\theta_1) = T_2 \cdot \cos(\theta_2)
    • In the vertical direction, the sum of the vertical components of the tensions must balance the total weight: T1sin(θ1)+T2sin(θ2)=Fcat+FdogT_1 \cdot \sin(\theta_1) + T_2 \cdot \sin(\theta_2) = F_{\text{cat}} + F_{\text{dog}}
  4. Solve for Tension T3T_3: Since rope 3 is horizontal and the system is in equilibrium, T3T_3 must be equal to the horizontal components of either T1T_1 or T2T_2.

Thus, T3=T1cos(θ1)T_3 = T_1 \cdot \cos(\theta_1).

Let me calculate the exact value of T3T_3.The tension in rope 3 (T3T_3) is approximately 35.36 N.

Would you like further details or clarification on any part of the solution?

Here are some related questions to deepen your understanding:

  1. How would the tension in rope 3 change if the steel dog were heavier?
  2. What happens to the angles of the ropes if rope 3 is not perfectly horizontal?
  3. How does changing the angle θ1\theta_1 affect the tension in rope 1?
  4. What would be the tension in rope 2 if we know the angle θ2\theta_2?
  5. How does static equilibrium apply to other structures like bridges or cranes?

Tip: In problems involving static equilibrium, always break the forces into horizontal and vertical components and apply the equilibrium conditions for each direction separately.

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Math Problem Analysis

Mathematical Concepts

Static Equilibrium
Trigonometry
Forces and Tension

Formulas

T₁ * cos(θ₁) = T₂ * cos(θ₂)
T₁ * sin(θ₁) + T₂ * sin(θ₂) = F_cat + F_dog
T₃ = T₁ * cos(θ₁)

Theorems

Equilibrium Conditions (Sum of forces in both horizontal and vertical directions must be zero)

Suitable Grade Level

Grades 10-12