Math Problem Statement

Arianna spends a winter day recording the temperature once every three hours for science class. At 9 am, the temperature was -6.7°F. Between 9am and noon, the temperature rose 10.7°F. Between noon and 3pm, the temperature went up 14.8°F. Between 3pm and 6pm, the temperature decreased by 12.9°F. What was the temperature at 6pm?

Solution

We can calculate the temperature at each time step by adding or subtracting the changes.

  1. Initial temperature at 9 am: 6.7F-6.7^\circ F

  2. Between 9 am and noon:
    The temperature rose by 10.7F10.7^\circ F.
    New temperature:
    6.7F+10.7F=4.0F-6.7^\circ F + 10.7^\circ F = 4.0^\circ F

  3. Between noon and 3 pm:
    The temperature rose by 14.8F14.8^\circ F.
    New temperature:
    4.0F+14.8F=18.8F4.0^\circ F + 14.8^\circ F = 18.8^\circ F

  4. Between 3 pm and 6 pm:
    The temperature decreased by 12.9F12.9^\circ F.
    New temperature:
    18.8F12.9F=5.9F18.8^\circ F - 12.9^\circ F = 5.9^\circ F

Thus, the temperature at 6 pm was 5.9F5.9^\circ F.

Would you like further details or have any other questions?

Here are five related questions:

  1. What would be the temperature at 9 pm if it decreased by 5°F after 6 pm?
  2. How would you calculate the average temperature change per hour during the day?
  3. If the temperature increased by 7.5°F every hour after 6 pm, what would it be at midnight?
  4. What if the initial temperature at 9 am was 0F0^\circ F? How would the result change?
  5. Can you create a temperature graph showing the changes during the day?

Tip: Always double-check units (e.g., °F or °C) to avoid calculation errors in temperature problems!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Arithmetic
Addition and Subtraction

Formulas

Temperature change = Initial temperature + Change

Theorems

-

Suitable Grade Level

Grades 5-6