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We are given the following information from the problem:

- The adults paid \$1200 altogether.
- The students paid \$640 altogether.
- The price of an adult ticket is \$60.
- There are 4 more teachers than parents.

The task is to find out how many parents were in the group.

Let:
- $ p $ represent the number of parents.
- $ t $ represent the number of teachers.
  
From the problem, we have:
1. $ t = p + 4 $ (since there are 4 more teachers than parents).
2. The total amount paid by adults is \$1200, and each adult (whether parent or teacher) paid \$60 for a ticket. Therefore, the number of adults is $ p + t $, and:
   \[
   60(p + t) = 1200
   \]
   Simplifying:
   \[
   p + t = 20
   \]
   
Substitute $ t = p + 4 $ into $ p + t = 20 $:
\[
p + (p + 4) = 20
\]
\[
2p + 4 = 20
\]
\[
2p = 16
\]
\[
p = 8
\]

Thus, there were **8 parents** in the group.

Would you like further details or clarifications? Here are five related questions to help expand on this concept:
1. How many teachers were there in the group?
2. How many adults attended the concert altogether?
3. What would the solution be if each adult ticket cost \$70 instead of \$60?
4. How much did each student pay for their ticket, given that they paid \$640 altogether?
5. What would happen if there were 5 more teachers than parents instead of 4?

**Tip:** Always write down key relationships between variables to make substitution in algebraic problems easier.

A group of teachers, parents, and students attended a concert. The adults paid $1,200 altogether and the students paid $640 altogether for their tickets. The price of an adult ticket was $60, and there were 4 more teachers than parents. How many parents were there in the group?

Learn how to solve a linear equation problem where adults paid $1,200 and students paid $640 for tickets. The adult ticket cost is $60, and there are 4 more teachers than parents. Find out how many parents attended the concert with step-by-step algebraic methods.

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