Math Problem Statement

Sea f(x) = e^(2x). a) Encontrar la expresión del polinomio de Taylor p_3(x) de orden 3 en x_0 = 0. b) Escribir la expresión del resto R_3(x). Estimar, acotando el resto, el error que se comete al calcular f(0,4) por medio de p_3(0,4).

Solution

The question involves finding the Taylor polynomial of a function and estimating the error of approximation. Here's the step-by-step solution:

Given the function:

f(x)=e2xf(x) = e^{2x}

Part (a): Find the Taylor polynomial p3(x)p_3(x) of order 3 at x0=0x_0 = 0.

The Taylor series of a function f(x)f(x) around x0=0x_0 = 0 is given by:

f(x)=f(0)+f(0)x+f(0)x22!+f(0)x33!+f(x) = f(0) + f'(0)x + \frac{f''(0)x^2}{2!} + \frac{f'''(0)x^3}{3!} + \cdots

We need the first three derivatives of f(x)=e2xf(x) = e^{2x}:

  1. f(x)=e2xf(x) = e^{2x}
  2. f(x)=2e2xf'(x) = 2e^{2x}
  3. f(x)=4e2xf''(x) = 4e^{2x}
  4. f(x)=8e2xf'''(x) = 8e^{2x}

Evaluating these at x=0x = 0:

  1. f(0)=e0=1f(0) = e^0 = 1
  2. f(0)=2e0=2f'(0) = 2e^0 = 2
  3. f(0)=4e0=4f''(0) = 4e^0 = 4
  4. f(0)=8e0=8f'''(0) = 8e^0 = 8

Thus, the Taylor polynomial of order 3 is:

p3(x)=1+2x+4x22!+8x33!p_3(x) = 1 + 2x + \frac{4x^2}{2!} + \frac{8x^3}{3!}

Simplifying:

p3(x)=1+2x+2x2+4x33p_3(x) = 1 + 2x + 2x^2 + \frac{4x^3}{3}

Part (b): Write the expression for the remainder R3(x)R_3(x). Estimate, by bounding the remainder, the error when calculating f(0.4)f(0.4) using p3(0.4)p_3(0.4).

The remainder term of the Taylor series is given by:

R3(x)=f(4)(c)x44!R_3(x) = \frac{f^{(4)}(c) x^4}{4!}

where cc is some value between 0 and xx. The fourth derivative of f(x)f(x) is:

f(4)(x)=16e2xf^{(4)}(x) = 16e^{2x}

To bound the error, we take the maximum value of f(4)(c)f^{(4)}(c) for c[0,0.4]c \in [0, 0.4]:

f(4)(c)16e2×0.4=16e0.8|f^{(4)}(c)| \leq 16e^{2 \times 0.4} = 16e^{0.8}

Thus, the bound for the remainder when x=0.4x = 0.4 is:

R3(0.4)16e0.8×(0.4)44!|R_3(0.4)| \leq \frac{16e^{0.8} \times (0.4)^4}{4!}

Calculating this will give the estimated error. Let me know if you would like the numerical estimation of this error!


Do you want details on the numerical estimation or have any questions? Here are some related questions for further practice:

  1. How do you find a Taylor polynomial of a different order for e2xe^{2x}?
  2. What changes if we expand the Taylor series around a different point, such as x=1x = 1?
  3. How does the error estimation differ if a higher-order term is considered?
  4. How do you calculate the error for different values of xx?
  5. What are the implications of using Taylor polynomials in approximations?

Tip: Always check the interval over which you're estimating the error to ensure the error bound calculation is accurate.

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Math Problem Analysis

Mathematical Concepts

Calculus
Taylor Series
Error Estimation

Formulas

Taylor Series: f(x) = f(0) + f'(0)x + (f''(0)x^2) / 2! + (f'''(0)x^3) / 3! + ...
Error Estimation: R_n(x) = (f^(n+1)(c) * x^(n+1)) / (n+1)!

Theorems

Taylor's Theorem

Suitable Grade Level

College Level Calculus