Math Problem Statement
Using the priority list T6, T5, T1, T7, T4, T3, T2, schedule the project below with two processors.
T1 (2)T2 (12)T3 (6)T4 (4)T5 (8)T6 (7)T7 (10)End[Graphs generated by this script: setBorder(60,30,60,30);initPicture(0,3,0,2); fontsize=14;fontstyle='none';marker="arrow";line([0,2],[1,2]);line([0,2],[1,1]);line([0,1],[1,1]);line([0,0],[2,1]);line([1,2],[2,2]);line([1,2],[2,1]);line([1,1],[2,2]);line([1,1],[2,1]);line([2,2],[3,1.5]);line([2,1],[3,1.5]);fontbackground='white';fontfill='blue';text([0,2],'T1 (2)','aboveleft');dot([0,2]);fontfill='blue';text([0,1],'T2 (12)','belowleft');dot([0,1]);fontfill='blue';text([0,0],'T3 (6)','belowleft');dot([0,0]);fontfill='blue';text([1,2],'T4 (4)','aboveleft');dot([1,2]);fontfill='blue';text([1,1],'T5 (8)','belowleft');dot([1,1]);fontfill='blue';text([2,2],'T6 (7)','aboveright');dot([2,2]);fontfill='blue';text([2,1],'T7 (10)','belowright');dot([2,1]);fontfill='blue';text([3,1.5],'End','aboveright');dot([3,1.5]);]
Task 4 is done by Select an answer Processor 1 Processor 2 starting at time
Task 6 is done by Select an answer Processor 1 Processor 2 starting at time
Solution
To solve this problem using the priority list method with two processors, we need to follow these steps:
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Assign Tasks to Processors Based on Priority:
- We use the priority list: T6, T5, T1, T7, T4, T3, T2.
- Assign the tasks to the processors according to their availability and the task durations.
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Calculate the Starting Times for Each Task:
- We must ensure that tasks are scheduled as early as possible, respecting the task dependencies (as indicated by the graph).
Step-by-Step Scheduling
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T6 (7 units):
- This is the highest-priority task, so it is assigned to Processor 1 at time 0.
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T5 (8 units):
- Assigned to Processor 2 at time 0.
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T1 (2 units):
- This task should ideally be assigned to a processor as soon as one becomes available.
- Processor 1 finishes T6 at time 7, so T1 can start at time 7.
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T7 (10 units):
- This should start as soon as a processor is free.
- Processor 2 will finish T5 at time 8, so T7 can start at time 8.
-
T4 (4 units):
- Processor 1 finishes T1 at time 9, so T4 can start at time 9.
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T3 (6 units):
- Processor 1 finishes T4 at time 13, so T3 can start at time 13.
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T2 (12 units):
- Processor 2 finishes T7 at time 18, so T2 can start at time 18.
Summary of Scheduling
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Processor 1:
- T6: Start at 0, End at 7
- T1: Start at 7, End at 9
- T4: Start at 9, End at 13
- T3: Start at 13, End at 19
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Processor 2:
- T5: Start at 0, End at 8
- T7: Start at 8, End at 18
- T2: Start at 18, End at 30
Answers to the Specific Questions:
- Task 4 is done by: Processor 1, starting at time 9.
- Task 6 is done by: Processor 1, starting at time 0.
Would you like more details on how this was calculated, or do you have any further questions?
Here are 8 related questions to expand your understanding:
- What are some other methods for task scheduling in a multi-processor system?
- How do task dependencies influence the scheduling order?
- What is a critical path, and how does it relate to task scheduling?
- How can scheduling algorithms be optimized for minimizing completion time?
- What happens if a task with a lower priority has a dependency on a higher-priority task?
- How does the introduction of more processors affect the scheduling strategy?
- What are the potential drawbacks of the priority list method?
- Can this method be applied to dynamic task scheduling where tasks are added during execution?
Tip: When scheduling tasks, always verify that the task dependencies are respected; this ensures that the final output will be logically consistent.
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Math Problem Analysis
Mathematical Concepts
Task scheduling
Priority list method
Multi-processor systems
Formulas
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Theorems
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Suitable Grade Level
Advanced
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