Math Problem Statement

Solution

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Math Problem Analysis

Mathematical Concepts

Differentiation
Tangent and Normal Lines
Point-Slope Form

Formulas

y = x√x - 3x
dy/dx = (3/2)√x - 3
Point-slope form: y - y₀ = m(x - x₀)
Tangent slope at x₀ = 9: mₜ = (3/2)√9 - 3
Normal slope mₙ = -1/mₜ

Theorems

Differentiation rules
Point-Slope Form for equations of lines

Suitable Grade Level

Undergraduate Level (Calculus)