Math Problem Statement

Find an equation of the tangent line to the parabola 𝑓(𝑥) = x^2+2x+2 a point (2,2)

Solution

To find the equation of the tangent line to the parabola f(x)=x2+2x+2f(x) = x^2 + 2x + 2 at the point (2,2)(2, 2), we need to follow these steps:

Step 1: Verify that the point lies on the curve

Substitute x=2x = 2 into the function f(x)f(x) to check if f(2)=2f(2) = 2.

f(2)=(2)2+2(2)+2=4+4+2=10f(2) = (2)^2 + 2(2) + 2 = 4 + 4 + 2 = 10

But the given point is (2,2)(2, 2), and we calculated f(2)=10f(2) = 10, not 2. This means the point (2,2)(2, 2) is not on the parabola f(x)=x2+2x+2f(x) = x^2 + 2x + 2, so there is no tangent line at this point.

Alternative Approach

Since there was likely a miscommunication with the given point, I suggest verifying the point or function again. If you want to work through this problem with a different point on the curve, feel free to provide more details.

Do you have any questions or want to clarify the problem?

Here are 5 related questions:

  1. How do you find the slope of a tangent line to a curve at a given point?
  2. What happens if the point does not lie on the curve?
  3. How can derivatives help in determining tangent lines?
  4. Can a point outside the curve have a unique tangent line?
  5. How can we generalize the formula for the equation of a tangent line?

Tip: When verifying whether a point is on a curve, always substitute the xx-coordinate into the equation and check if the yy-value matches.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Quadratic Functions
Tangent Line

Formulas

f(x) = ax^2 + bx + c
Derivative of f(x): f'(x) = 2ax + b
Equation of tangent line: y = m(x - x1) + y1

Theorems

Derivative as the slope of the tangent line

Suitable Grade Level

Grades 10-12