To find the equation of the tangent to the curve $f(x) = x^2 - 9$ at $x = 3$, we will follow these steps:

1. Find the derivative $f'(x)$: The derivative of $f(x)$ gives us the slope of the tangent at any point on the curve. $f(x) = x^2 - 9 \implies f'(x) = 2x$

2. Evaluate $f'(3)$ to find the slope at $x = 3$: $f'(3) = 2(3) = 6$ So, the slope of the tangent at $x = 3$ is 6.

3. Find the point on the curve at $x = 3$: We need the coordinates of the point where the tangent touches the curve. $f(3) = 3^2 - 9 = 9 - 9 = 0$ Therefore, the point of tangency is $(3, 0)$.

4. **Write the