Math Problem Statement

Calculate the reliability of each system shown in the diagram. Components A, B, C, D, and E function properly with probabilities of 0.10, 0.15, 0.10, 0.20, and 0.25, respectively. Calculate the overall system reliability.

Solution

The image shows a logic circuit where components AA, BB, CC, DD, and EE have individual failure probabilities of 0.10, 0.15, 0.10, 0.20, and 0.25, respectively. The problem asks for the system's reliability calculation.

Circuit Analysis

The system contains:

  1. Two parallel branches:
    • Top branch: AA and DD in series.
    • Bottom branch: BB, CC, and EE in series.
  2. These two branches are connected in parallel, meaning the system will fail only if both branches fail.

Step-by-Step Solution

1. Reliability of Each Branch

  • Reliability of the Top Branch (Series of AA and DD): For components in series, the overall reliability is the product of the individual reliabilities: Rtop=(1PA)×(1PD)=(10.10)×(10.20)=0.90×0.80=0.72R_{\text{top}} = (1 - P_A) \times (1 - P_D) = (1 - 0.10) \times (1 - 0.20) = 0.90 \times 0.80 = 0.72

  • Reliability of the Bottom Branch (Series of BB, CC, and EE): Similarly, the reliability for components in series is the product of the individual reliabilities: Rbottom=(1PB)×(1PC)×(1PE)=(10.15)×(10.10)×(10.25)R_{\text{bottom}} = (1 - P_B) \times (1 - P_C) \times (1 - P_E) = (1 - 0.15) \times (1 - 0.10) \times (1 - 0.25) Rbottom=0.85×0.90×0.75=0.57375R_{\text{bottom}} = 0.85 \times 0.90 \times 0.75 = 0.57375

2. System Reliability (Parallel Connection)

The system reliability for parallel branches is: Rsystem=1((1Rtop)×(1Rbottom))R_{\text{system}} = 1 - \left( (1 - R_{\text{top}}) \times (1 - R_{\text{bottom}}) \right) Substitute the values: Rsystem=1((10.72)×(10.57375))=1(0.28×0.42625)=10.11935=0.88065R_{\text{system}} = 1 - \left( (1 - 0.72) \times (1 - 0.57375) \right) = 1 - (0.28 \times 0.42625) = 1 - 0.11935 = 0.88065

Final Answer:

The system reliability is approximately 0.8810.881 (rounded to three decimal places).


Do you have any further questions or would you like more details? Here are five related questions for deeper understanding:

  1. What is the significance of series and parallel arrangements in reliability problems?
  2. How does increasing the number of components in a series affect the system's overall reliability?
  3. How can one optimize system reliability when dealing with components of varying failure probabilities?
  4. Can you explain how redundancy improves the reliability of a system?
  5. What other factors, besides failure probabilities, could influence real-world reliability analysis?

Tip: In reliability problems, remember that for series components, the system is only as reliable as the weakest link, while parallel arrangements help improve overall reliability by providing alternative pathways.

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Math Problem Analysis

Mathematical Concepts

Reliability Engineering
Series and Parallel Systems
Probability

Formulas

R_{top} = (1 - P_A) * (1 - P_D)
R_{bottom} = (1 - P_B) * (1 - P_C) * (1 - P_E)
R_{system} = 1 - ((1 - R_{top}) * (1 - R_{bottom}))

Theorems

System reliability for series and parallel connections

Suitable Grade Level

Undergraduate Engineering