Math Problem Statement

Amy owns an organic nut shop. A customer buys 5 pounds of walnuts and 3 pounds of pecans for $21. Another customer buys 4 pounds of walnuts and 8 pounds of pecans for $28.50. What is the cost of one pound of pecans?

Solution

The problem in the image reads:

Amy owns an organic nut shop. A customer buys 5 pounds of walnuts and 3 pounds of pecans for $21. Another customer buys 4 pounds of walnuts and 8 pounds of pecans for $28.50. What is the cost of one pound of pecans?

Step-by-step solution:

We need to set up a system of equations to solve for the prices of walnuts and pecans.

Let:

  • ww be the price per pound of walnuts.
  • pp be the price per pound of pecans.

From the two transactions:

  1. 5w+3p=215w + 3p = 21 (First customer buys 5 pounds of walnuts and 3 pounds of pecans for $21)
  2. 4w+8p=28.504w + 8p = 28.50 (Second customer buys 4 pounds of walnuts and 8 pounds of pecans for $28.50)

Solving the system of equations:

Step 1: Multiply the first equation by 8 and the second equation by 3 to align the coefficients of pp:

8(5w+3p)=8(21)40w+24p=1688(5w + 3p) = 8(21) \quad \Rightarrow \quad 40w + 24p = 168 3(4w+8p)=3(28.50)12w+24p=85.503(4w + 8p) = 3(28.50) \quad \Rightarrow \quad 12w + 24p = 85.50

Step 2: Subtract the second equation from the first:

(40w+24p)(12w+24p)=16885.50(40w + 24p) - (12w + 24p) = 168 - 85.50 28w=82.5028w = 82.50 w=82.5028w=2.95w = \frac{82.50}{28} \quad \Rightarrow \quad w = 2.95

So, the price of one pound of walnuts is $2.95.

Step 3: Substitute w=2.95w = 2.95 into the first equation to solve for pp:

5(2.95)+3p=215(2.95) + 3p = 21 14.75+3p=2114.75 + 3p = 21 3p=2114.753p=6.253p = 21 - 14.75 \quad \Rightarrow \quad 3p = 6.25 p=6.253p=2.08p = \frac{6.25}{3} \quad \Rightarrow \quad p = 2.08

So, the price of one pound of pecans is $2.08.


Would you like more details or explanations on any part of the solution? Here are five related questions you can consider:

  1. How would the system of equations change if the prices of walnuts and pecans were different?
  2. What would happen if a third transaction was introduced? Could we solve for both prices without a system of equations?
  3. How can this method be applied to other two-variable cost problems?
  4. Can we solve this system of equations using a matrix method, such as Gaussian elimination?
  5. How does the substitution method compare to the elimination method in terms of efficiency?

Tip: When solving systems of equations, it can be helpful to align coefficients to simplify the elimination process.

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Math Problem Analysis

Mathematical Concepts

Algebra
Systems of Linear Equations

Formulas

w = (TotalCost - PecansCost) / WalnutQuantity
p = (TotalCost - WalnutsCost) / PecansQuantity

Theorems

Linear Equation Elimination Method

Suitable Grade Level

Grades 8-10