Math Problem Statement

Suppose that g ∘ f is surjective. Is f surjective? Is g surjective? Justify your answer.

Solution

We are given that gfg \circ f (the composition of gg and ff) is surjective, and we need to determine whether ff or gg must also be surjective, justifying the answers.

Recall Definitions:

  • A function is surjective (onto) if every element of the codomain has a preimage in the domain. In other words, for a function h:ABh: A \to B, for every bBb \in B, there exists some aAa \in A such that h(a)=bh(a) = b.

Now, let’s examine each case.

1. Is ff surjective?

To answer this, we need to consider the relationship between gfg \circ f being surjective and the properties of ff.

  • Let f:ABf: A \to B and g:BCg: B \to C.
  • Since gfg \circ f is surjective, for every cCc \in C, there exists some aAa \in A such that g(f(a))=cg(f(a)) = c.

However, this does not imply that ff itself is surjective. The reason is that ff maps from AA to BB, but the fact that gfg \circ f is surjective tells us only that the elements of CC are covered, not that all elements of BB are covered by ff.

Thus, ff is not necessarily surjective.

2. Is gg surjective?

Yes, gg must be surjective.

Here's why: Since gfg \circ f is surjective, for every cCc \in C, there exists some aAa \in A such that g(f(a))=cg(f(a)) = c. This implies that for every cCc \in C, there is some element b=f(a)Bb = f(a) \in B such that g(b)=cg(b) = c. Thus, gg must cover all elements of CC by taking preimages from BB, which means gg is surjective.

Summary:

  • ff is not necessarily surjective.
  • gg must be surjective.

Do you want further details or have any questions?

Here are 5 related questions to expand on this concept:

  1. What would happen if ff were injective but not surjective in this scenario?
  2. Can you give an example where gfg \circ f is surjective but ff is not?
  3. How does injectivity of gg affect the surjectivity of gfg \circ f?
  4. What if both ff and gg were injective—how would that impact gfg \circ f?
  5. How do surjective and injective functions differ in terms of their composition?

Tip: When working with compositions of functions, always carefully consider how the properties (injectivity, surjectivity) of each function impact the overall behavior of the composition.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Function Composition
Surjectivity

Formulas

g ∘ f(x) = g(f(x))

Theorems

Surjective Functions Theorem

Suitable Grade Level

Undergraduate Level (Mathematics)