To calculate the surface area of the triangular prism, we will calculate the areas of all the individual faces shown on the net and sum them up. Here’s the breakdown:

1. Two triangular faces:

Each triangular face has:

• Base = $12 \, \text{m}$
• Height = $9 \, \text{m}$

The area of one triangle: $\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 12 \times 9 = 54 \, \text{m}^2$ There are two identical triangular faces: $\text{Total triangular area} = 2 \times 54 = 108 \, \text{m}^2$

2. Three rectangular faces:

• Rectangle 1 (bottom):

  • Dimensions: $12 \, \text{m} \times 16 \, \text{m}$
  • Area: $\text{Area} = 12 \times 16 = 192 \, \text{m}^2$

• Rectangle 2 (side):

  • Dimensions: $15 \, \text{m} \times 16 \, \text{m}$
  • Area: $\text{Area} = 15 \times 16 = 240 \, \text{m}^2$

• Rectangle 3 (side):

  • Dimensions: $9 \, \text{m} \times 16 \, \text{m}$
  • Area: $\text{Area} = 9 \times 16 = 144 \, \text{m}^2$

3. Total Surface Area:

Add all the areas together: $\text{Total Surface Area} = 108 + 192 + 240 + 144 = 684 \, \text{m}^2$

Final Answer:

The surface area of the triangular prism is: $\boxed{684 \, \text{m}^2}$

Let me know if you would like a detailed explanation of any part or further assistance!