Math Problem Statement
Consider the parametric equations below. x = sin2(t), y = sin(2t), 0 β€ t β€ π 2 Set up an integral that represents the area of the surface obtained by rotating the given curve about the x-axis.
Solution
To set up the integral representing the surface area obtained by rotating the parametric curve given by , about the -axis, we'll use the surface area formula for a parametric curve rotated about the -axis:
Given:
- The parameter range is
Step 1: Compute and
Step 2: Set up the surface area integral
Substitute the values of , , and into the surface area formula:
Step 3: Simplify the square root expression
The term inside the square root simplifies as follows:
Thus, the integral becomes:
This is the integral representing the surface area of the curve rotated about the -axis.
Would you like me to proceed with further simplification or evaluation of this integral?
Related questions:
- What is the physical significance of the surface area obtained by rotating a curve?
- How does the parametric representation affect the surface area calculation for rotational surfaces?
- Can surface area integrals be evaluated for curves rotated around the -axis instead of the -axis?
- How would you handle the surface area if the limits of the parameter were different?
- How does the shape of the curve affect the complexity of the surface area integral?
Tip:
When solving problems involving surface areas of rotation, always check if there's symmetry that can simplify the integral before proceeding with full evaluation.
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Math Problem Analysis
Mathematical Concepts
Parametric Equations
Surface Area of Revolution
Integral Calculus
Formulas
Surface area formula for a parametric curve about the x-axis: A = β« 2Οy β((dx/dt)^2 + (dy/dt)^2) dt
dx/dt = 2sin(t)cos(t) = sin(2t)
dy/dt = 2cos(2t)
Theorems
Surface Area of Revolution
Chain Rule for Derivatives
Suitable Grade Level
Grades 11-12 or Early College
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