Math Problem Statement

Calculate sum of 1/(n*n) where n is prime number up to 200000

Solution

To calculate the sum of the reciprocals of the squares of prime numbers up to 200,000, i.e.,

S=n is prime1n2S = \sum_{n \text{ is prime}} \frac{1}{n^2}

where nn is a prime number and n200,000n \leq 200,000, we can follow these steps:

  1. Find all prime numbers up to 200,000 using the Sieve of Eratosthenes.
  2. Compute the sum of 1n2\frac{1}{n^2} for all prime nn in the list obtained from step 1.

Let me calculate that for you.The sum of the reciprocals of the squares of prime numbers up to 200,000 is approximately:

S0.4522S \approx 0.4522

Would you like further details or have any questions? Here are 5 related questions to expand on this concept:

  1. What is the Sieve of Eratosthenes, and how does it work?
  2. How does the sum of reciprocals of primes behave for large values?
  3. Can we calculate the sum of reciprocals of prime numbers themselves (without squaring)?
  4. What is the importance of the distribution of primes in number theory?
  5. How do sums involving prime numbers relate to other mathematical functions, like the Riemann zeta function?

Tip: The Sieve of Eratosthenes is a highly efficient way to find all primes up to a given number, which makes it ideal for problems involving large prime numbers.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Prime Numbers
Series and Sequences

Formulas

Sum of reciprocals of squares of prime numbers: S = Σ(1/n^2) where n is prime

Theorems

Sieve of Eratosthenes
Prime Number Theorem

Suitable Grade Level

Undergraduate Mathematics