The image shows the formula for the sum of squares of the first $n$ natural numbers:

$\sum_{i=1}^{n} i^2 = 1^2 + 2^2 + 3^2 + \cdots + n^2 = \frac{n(n+1)(2n+1)}{6}$

This equation expresses the sum of squares as a closed-form formula, which simplifies calculating the sum of squares for large $n$ without manually computing each square. Here's a breakdown of the formula:

• $n$: The number of terms (natural numbers) for which you want to calculate the sum of squares.
• $\sum_{i=1}^{n} i^2$: The summation notation representing the sum of squares of all integers from 1 to $n$.
• The right-hand side formula: $\frac{n(n+1)(2n+1)}{6}$ efficiently computes this sum.

For example:

• If $n = 3$, the sum of squares is ( 1^2 + 2^2 + 3^2 = 1 + 4 +