The sum of the first \(n\) natural numbers is given by the formula:

\[
S_n = \frac{n(n + 1)}{2}
\]

Where:
- \(S_n\) is the sum of the first \(n\) natural numbers,
- \(n\) is the number of terms.

### Example:
For \(n = 5\):

\[
S_5 = \frac{5(5 + 1)}{2} = \frac{5 \times 6}{2} = 15
\]

So, the sum of the first 5 natural numbers is 15.

Would you like a further explanation or to try an example with a different value of \(n\)?

### Related questions:
1. What is the sum of the first 100 natural numbers?
2. How does this formula come about?
3. Can this formula be used for non-natural numbers (like fractions)?
4. How does the formula change for odd or even numbers only?
5. What is the sum of the first 50 even numbers?

**Tip**: Using this formula makes it easier to find the sum without having to add each term individually!

Learn how to find the sum of the first n natural numbers using the formula S_n = n(n + 1) / 2. This solution demonstrates the calculation for n = 5 and provides a general method for solving such problems, suitable for students in Grades 5-7.

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