The image you uploaded contains a sum of squares from 1 to 100, written as:

$1^2 + 2^2 + 3^2 + \dots + 100^2$

This is a well-known series, and the formula to find the sum of squares of the first $n$ integers is:

$S_n = \frac{n(n+1)(2n+1)}{6}$

For $n = 100$, the sum is:

$S_{100} = \frac{100(100+1)(2 \times 100 + 1)}{6}$

Let me compute that for you. Calculating the sum of squares of the first 100 integers n = 100 sum_of_squares = (n * (n + 1) * (2 * n + 1)) / 6 sum_of_squaresThe sum of squares from 1 to 100 is:

$1^2 + 2^2 + 3^2 + \dots + 100^2 = 338350$

Would you like further details on how this formula works, or do you have any other questions related to this topic?

Here are some related questions you might find interesting:

1. How can you prove the formula for the sum of squares?
2. What are the sum formulas for other powers (e.g., cubes, fourth powers)?
3. How can this sum formula be generalized for any $n$?
4. What are some real-life applications of sum of squares formulas?
5. How do you compute sums of series for non-square powers?

Tip: The sum of squares formula helps in deriving many useful results in physics and engineering, especially in analyzing distributions and variances.